1/169) / (1/3
1/169 *3
3/169
Hope this helps :)
Answer:
Step-by-step explanation:
Trapezoid
Solve for area
A=44
a Base
5
b Base
17
h Height
4
Answer:
Step-by-step explanation:
rate = a
a = -16-(-11)/9-6
a= -5/3
The mass of radioactive material remaining after 50 years would be 48.79 kilograms
<h3>How to determine the amount</h3>
It is important to note that half - life is the time it takes for the amount of a substance to reduce by half its original size.
Given the radioactive decay formula as
m(t)=120e−0.018t
Where
t= 50 years
m(t) is the remaining amount
Substitute the value of t


Find the exponential value
m(t) = 48.788399
m(t) = 48.79 kilograms to 2 decimal places
Thus, the mass of radioactive material remaining after 50 years would be 48.79 kilograms
Learn more about half-life here:
brainly.com/question/26148784
#SPJ1
Answer:
The vertex of the parabola is at equal distance between focus and the directrix. If F is the focus of the parabola, V is the vertex and D is the intersection point of the directrix and the axis of symmetry, then V is the midpoint of the line segment ¯FD
Step-by-step explanation:
answer 3rd