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Nuetrik [128]
2 years ago
9

Find the area of the unshaded region for these two problems​

Mathematics
1 answer:
Grace [21]2 years ago
5 0

1. Area of the right angled ∆ = 1/2 × base × height

height = 16m

base = √20² – 16²

= √400 –256

= √144

= 12 m

Area of the unshaded portion

= 1/2 × base × height

= 1/2 × 12 × 16

= 96m²

2. Area of the rectangle = 300ft × 150ft

= 45000sq. ft

Area of the shaded portion = 100² + (1/2×b×h)

= 10000 + (1/2×120×150)

= 10000 + 9000

= 19000 sq. ft

Area of the unshaded part of the rectangle

= (45000 – 19000)sq. ft

= 26000 sq. ft

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Find the value of x in the isosceles triangle shown below.​
dybincka [34]

USING PYTHAGORAS THEORAM,

x²+3²= 5²

x²+9= 25

x²= 25-9 = 16

x= √16

x= 4

OPTION D

6 0
2 years ago
For the 2015 Intel Science Fair, two brothers in high school recruited 47 of their classmates to take part in a two-stage study.
kvv77 [185]

Answer:

a) 47

b) 3

c)  1

d) 2

e) 47

f) 3

Step-by-step explanation:

read the textbook

8 0
3 years ago
Read 2 more answers
WILL MARK BRAINLIEST
dsp73
<h3>Refer to the diagram below</h3>
  1. Draw one smaller circle inside another larger circle. Make sure the circle's edges do not touch in any way. Based on this diagram, you can see that any tangent of the smaller circle cannot possibly intersect the larger circle at exactly one location (hence that inner circle tangent cannot be a tangent to the larger circle). So that's why there are no common tangents in this situation.
  2. Start with the drawing made in problem 1. Move the smaller circle so that it's now touching the larger circle at exactly one point. Make sure the smaller circle is completely inside the larger one. They both share a common point of tangency and therefore share a common single tangent line.
  3. Start with the drawing made for problem 2. Move the smaller circle so that it's partially outside the larger circle. This will allow for two different common tangents to form.
  4. Start with the drawing made for problem 3. Move the smaller circle so that it's completely outside the larger circle, but have the circles touch at exactly one point. This will allow for an internal common tangent plus two extra external common tangents.
  5. Pull the two circles completely apart. Make sure they don't touch at all. This will allow us to have four different common tangents. Two of those tangents are internal, while the others are external. An internal tangent cuts through the line that directly connects the centers of the circles.

Refer to the diagram below for examples of what I mean.

5 0
3 years ago
A^4 + 2b OVER a; if a =3 and b = 12
Tems11 [23]

Answer:

105

Step-by-step explanation:

Given : a = 3, b = 12

3 ⁴ = 81

2 x 12 = 24

Result:

81 + 24

= 105

6 0
3 years ago
Lester orders a book for $35. He must pay a shipping charge of 12%. Show how to find 12% of $35 by using benchmark percents, the
Elis [28]

Answer:

$4.2

Step-by-step explanation:

1. 12%=0.12

2. 0.12 of $35 = 0.12 × $35

3. = $4.2

8 0
2 years ago
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