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3 years ago

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Two square rooms have total floor area of 89cm².One room is 3m longer each way than the other,Find the dimension of the two room

s

1 answer:

nlexa [21]3 years ago

7 0

Answer:

5 m

8 m

Step-by-step explanation:

Area of square = s² ; s = side length

Let the area of each room equal to x and y

x + y = 89cm²

If x = smaller room

y = x + 3 in dimension

Hence,

x² + (x + 3)² = 89

(x +3)(x +3) = x² + 3x + 3x + 9

x² + x² + 3x + 3x + 9 = 89

2x² + 6x + 9 = 89

2x² + 6x - 80 = 0

x² + 3x - 40 = 0

x² + 8x - 5x - 40 = 0

x(x + 8) - 5(x + 8) = 0

x + 8 = 0 ;

x - 5 = 0

x = - 8 or x = 5

Dimension can't be negative :

So, x = 5

Samller square = x = 5

Larger square = x + 3 = 5 + 3 = 8

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3 years ago

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3 years ago

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Sergeu [11.5K]

Answer:

lesser x = -1.84
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Step-by-step explanation:

Given the expression

$\left(x+5\right)^2-10=0$

Add 10 to both sides

$\left(x+5\right)^2-10+10=0+10$

Simplify

$\left(x+5\right)^2=10$

$\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

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so

$x+5=-\sqrt{10}$

Subtract 5 from both sides

$x+5-5=-\sqrt{10}-5$

Simplify

$x=-\sqrt{10}-5$

$\:x=-8.2$

As -1.84 > -8.16

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lesser x = -1.84
lesser x = -8.16

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3 years ago