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damaskus [11]
3 years ago
9

Solve for x. Enter the solutions from least to greatest. (x+15)^2-10=0

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
7 0

Answer:

  • lesser x = -1.84
  • lesser x = -8.16

Step-by-step explanation:

Given the expression

\left(x+5\right)^2-10=0

Add 10 to both sides

\left(x+5\right)^2-10+10=0+10

Simplify

\left(x+5\right)^2=10

\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

solve

x+5=\sqrt{10}

Subtract 5 from both sides

x+5-5=\sqrt{10}-5

x=\sqrt{10}-5

x=-1.8

so

x+5=-\sqrt{10}

Subtract 5 from both sides

x+5-5=-\sqrt{10}-5

Simplify

x=-\sqrt{10}-5

\:x=-8.2

As -1.84 > -8.16

so

  • lesser x = -1.84
  • lesser x = -8.16
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---

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