The answer to your problem is -2.1.
Hello there!
I'm assuming since there is no question, that you want an explanation for composite functions.
Today, I want to introduce you to a very new way of looking at functions. Think of a function as a machine. I'll call this machine f. When you plug something into this machine, it is an x-value. The machine changes the x-value into a new value which is called a y-value. This is how a function works.
With composite functions though, things get a little bit tricky. To make f(g(x)), you need to plug in x into the g machine, and it will give you an output. (y-value) The next thing you do is take that y-value and plug it into the g machine. The g machine then gives you a new value. This value is f(g(x)).
Let's do an example together...
f(x)=3x and g(x)=x²+4
if we want f(g(x)), first plug in x to the g machine. when plugging in x to the g machine, we get x²+4 as given in the question.
Now we must plug in g(x) into the f machine. Since g(x) is x²+4, we just replace x with x²+4.
We get 3(x²+4)
This means that f(g(x))=3(x²+4)
NOTE: If you are seeking help with an actual question, please message me in the comments and I will assist you shortly!
I hope this helps!
Best wishes :)
Answer:
$79
Step-by-step explanation:
Answer:
7x^2y(2x-3y)
Step-by-step explanation:
Factor 7x^2y out of 14x^3y-21x^2y^2
Answer:
![ln(27c^3)](https://tex.z-dn.net/?f=ln%2827c%5E3%29)
Step-by-step explanation:
Given: ![3ln(3)+3ln(c)](https://tex.z-dn.net/?f=3ln%283%29%2B3ln%28c%29)
If there is a coefficient in front of a
or
, that means it becomes an exponent.
![ln(3^3)+ln(c^3)](https://tex.z-dn.net/?f=ln%283%5E3%29%2Bln%28c%5E3%29)
Simplify the exponent.
![ln(27)+ln(c^3)](https://tex.z-dn.net/?f=ln%2827%29%2Bln%28c%5E3%29)
When there is addition between two logarithms or natural logarithms, it means they multiply together.
![ln(27c^3)](https://tex.z-dn.net/?f=ln%2827c%5E3%29)