Given that,
Sample size= 83
Mean number= 39.04
Standard deviation= 11.51
We know the critical t-value for 95% confidence interval which is equal to 1.989.
We also know the formula for confidence interval,
CI=( mean number - critical t-value*standard deviation/(sample size)^(1/2), mean number + critical t-value*standard deviation/(sample size)^(1/2))
So, we have
CI= (39.04 - 1.989*11.51/83^(1/2), 39.04 + 1.989*11.51/83^(1/2)
CI= (39.04 - 2.513,39.04 + 2.513)
CI= (36.527,41.553)
Therefore, 95% confidence interval for these data is (36.527,41.553), and this result interpret that the true value for this survey sample lie in the interval (36.527,41.553).
Six dozen cupcakes is 72. So in this case Kailyn made 88 cupcakes, but that was 72 more than Melissa made so Melissa only made 16.
Answer:
a. £24,714.29
b. £16,833.33
Step-by-step explanation:
The calculation of mean income is given below:-
Mean income = Total addition of salaries ÷ Number of workers
= £9,500 + £25,000 + £13,250 + £72,000 + £12,750 + £29,500 + £11,000
= £173,000 ÷ 7
= £24,714.29
Now,
the Mean income excluding Deva's salary:
= Formula of Mean income
= Total addition of salaries excluding Deva salary ÷ Number of workers
= (£9,500 + £25,000 + £13,250 + £12,750 + £29,500 + £11,000) ÷ 6
= £101,000 ÷ 6
= £16,833.33
Answer:
she can give out candy to 62 kids
Step-by-step explanation:
there is ur answer
Answer:
2
Step-by-step explanation:
y2 - y1 / x2 - x1
-2 - 4 / -1 - (-4)
-2 - 4 / -1 + 4
-6 / 3
2
