Equation of circle is 
Step-by-step explanation:
The standard form of the equation of circle is:

where (h,k) is the center of the circle and r is the radius of circle.
We need to find the radius of circle r by using distance formula:
![[tex]r=d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}\\r=d=\sqrt{(4-0)^2+(-4-2)^2}\\r=d=\sqrt{(4)^2+(-6)^2}\\r=d=\sqrt{16+36}\\r=d=\sqrt{52}](https://tex.z-dn.net/?f=%5Btex%5Dr%3Dd%3D%5Csqrt%7B%28x_%7B2%7D-x_%7B1%7D%29%5E2%2B%28y_%7B2%7D-y_%7B1%7D%29%5E2%7D%5C%5Cr%3Dd%3D%5Csqrt%7B%284-0%29%5E2%2B%28-4-2%29%5E2%7D%5C%5Cr%3Dd%3D%5Csqrt%7B%284%29%5E2%2B%28-6%29%5E2%7D%5C%5Cr%3Dd%3D%5Csqrt%7B16%2B36%7D%5C%5Cr%3Dd%3D%5Csqrt%7B52%7D)
r=√52
and r^2= 52
Putting values of r^2=52 and value of center (h,k)=(0,2)
the equation of Circle is:

Keywords: Equation of circle
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In mathematical expression, it would be: x - y/2
Hope this helps!
Answer:
-4.5
Step-by-step explanation:
Answer:
BE = 49
Step-by-step explanation:
In triangle BDC
65^2=56^2+BD^2
65^2-56^2=BD^2
4225-3136=BD^2
1089=BD^2
33=BD
In triangle FDE
65^2=63^2+DE^2
4225-3969=DE^2
256 = DE^2
16=DE
since ED+DB=BE
THEREFORE
16+33=BE
49=BE