2 years ago

Hi! This is a fairly simple question for some of you, but I wanted to ask, how do you solve this? Thank you so much! :)

1 answer:

givi [52]2 years ago

5 0

Hey I got to it c c c c c c c c c c c c c c c c 8 8

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Serjik [45]

Try Photomath; to see if it helps

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2 years ago

timurjin [86]

Only 3 is false, because of spare minus.

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3 years ago

Mumz [18]

Answer:

n = 5

Step-by-step explanation:

Coordinate of P = (n,3)

R is on y-axis & the y-coordinate of P & R are equal. So coordinate of R = (3,0)

Coordinate of Q = (n,-2)

Using distance formula,

Distance between P & Q =

$\sqrt{ {( n - n}) ^{2} + {( 3- ( - 2) })^{2} }$

$= > \sqrt{ {(3 + 2)}^{2} } = \sqrt{ {5}^{2} } = 5$

Distance between P & R =

$\sqrt{ {(n - 0)}^{2} + {(3 - 3)}^{2} }$

$= > \sqrt{ {n}^{2} } = n$

But in question it is given that distance between P & Q is equal to the distance between P & R. So,

$n = 5$

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2 years ago

Leno4ka [110]

The answer is

$8 \frac{2}{5}$

6 0

2 years ago

Damm [24]

I'm not sure

Step-by-step explanation:

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2 years ago