Question

A license plate begins with three letters. If the possible letters are A, B, C, D and E, how many different permutations of these letters can be made if no letter is used more than once?

Answer 1

Answer:

60 different permutations of these letters can be made.

Step-by-step explanation:

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

$P_{(n,x)} = \frac{n!}{(n-x)!}$

How many different permutations of these letters can be made if no letter is used more than once?

3 letters from a set of 5. So

$P_{(5,3)} = \frac{5!}{(5-3)!} = \frac{5!}{2!} = 5*4*3 = 60$

60 different permutations of these letters can be made.