1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Iteru [2.4K]
3 years ago
15

A frog leaps straight up from the ground and is caught when he reaches his maximum height 2\,\text s2s2, start text, s, end text

later by a little girl. We want to find the vertical velocity of the frog at the moment that it left the ground. Which kinematic formula would be most useful to solve for the target unknown
Physics
2 answers:
irina [24]3 years ago
6 0

Correct question is;

A frog leaps straight up from the ground and is caught when he reaches his maximum height 2 seconds later by a little girl. We want to find the vertical velocity of the frog at the moment that it left the ground. Which kinematic formula would be most useful to solve for the target unknown? Assume the positive direction is upward and air resistance is negligible.

Answer:

v = u + at

Explanation:

We are given time taken to reach maximum height to be 2 seconds.

We also know that since it's going upwards against gravity, our acceleration due to gravity will be g = -9.8 m/s²

Now, since we have values of g and t and we know that at maximum height vertical component of velocity is zero.

Thus, we can use Newton's first equation of motion to solve for the vertical velocity at which it left the ground.

Thus;

v = u + at

Where v is velocity at maximum height and u is velocity at which it left the ground.

PIT_PIT [208]3 years ago
3 0

Answer:

ye

Explanation:

ye

You might be interested in
What should be done to lift the same load by applying less effort on an inclined plane​
Scorpion4ik [409]

Answer:

Reduce the friction at the surface

Explanation:

If you can reduce the friction between the load and the plane less effort will be required as you are not having to apply effort to overcome friction.

5 0
2 years ago
True or False: Tests given in school have little relation to choosing a job
TiliK225 [7]
True because school doesn't dictate what job you want in the future
5 0
3 years ago
Read 2 more answers
How far will a man travel in 15 min driving his car down the highway at an average speed of 24 m/?s
emmasim [6.3K]

Answer:

21.6 km

Explanation:

15×60×24 = 21600 m

\frac{21600}{1000}= 21.6 km

7 0
3 years ago
How many sides and points do a hexagon have
tamaranim1 [39]
A hexagon has 6 sides
8 0
4 years ago
Read 2 more answers
Okay! Last question was a warm-up question. And now to get your brain thinking some more, how about another one?:
den301095 [7]
The correct answer is a fishhook
5 0
3 years ago
Other questions:
  • At what speed do a bicycle and its rider, with a combined mass of 100 kg, have the same momentum as a 1400 kg car traveling at 2
    15·1 answer
  • What are the types of energies released when a candle burns?
    15·2 answers
  • Where is the frequency of ultrasound in relation to the range of human ability to hear
    12·2 answers
  • Originally 21 acts were tentatively scheduled to perform at the arena; only 10 have been booked. What is the shortfall if the ot
    5·1 answer
  • Squid and Octolules are propelled by expelting water, which is maintained in a body cavity. A squid of 6.5 kg (including water i
    10·1 answer
  • How many board feet of lumber are needed assuming 200 lin. Ft. of 2""x 6"" lumber a. 12 b. 16.67 c. 120 d. 200
    15·1 answer
  • What is the net force acting on a 15kg sled that accelerates at 5 m/s/s *
    15·1 answer
  • What is the equation to find the ima (ideal mechanical advantage of the wheel and axle?
    14·1 answer
  • Phương trình trạng thái tổng quát của khí lí tưởng diễn tả là​
    12·1 answer
  • A(n) 636 kg elevator starts from rest. It moves upward for 4.5 s with a constant acceleration until it reaches its cruising spee
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!