A spring scale measures weight because <span>It works by Hooke's Law, which states that the force needed to extend a </span>spring<span> is proportional to the distance that </span>spring<span> is extended from its rest position. Therefore, the </span>scale<span> markings on the </span>spring<span> balance are equally spaced. A </span>spring scale<span> can</span>not measure mass<span>, only </span>weight<span>. hope that helped</span>
Resolution in this sentence refers to a solution to the problem
B, since it is the only one that actually conserves matter for certain. In each of the others, matter could still be imbalanced, since for A, for example, it could be 5 Carbons on the right and 5 Chlorines on the left, and that would not balance.
Answer:
True
Explanation:
As the formula for magnitude of a vector v and their components
is

Since
, this means the sum of them,
, is always greater or equal to 
Yes D is definitely the answer
<em>V</em><em>=</em><em>I×</em><em>R</em>
<em>V</em><em>=</em><em>0</em><em>.</em><em>0</em><em>2</em><em>5</em><em>×</em><em>3</em><em>6</em>
<em>V</em><em>=</em><em>0</em><em>.</em><em>9</em><em> </em><em>sa</em><em>me</em><em> </em><em>as</em><em> </em><em>0</em><em>.</em><em>9</em><em>0</em>