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Andrei [34K]
3 years ago
8

Explain the purpose of oxidation numbers?

Physics
1 answer:
morpeh [17]3 years ago
5 0
It’s important to know if an atom loses or gains electrons when combining with other atoms to form compounds
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Choose the statement that is a misconception about a system in chemical equilibrium. (2 points) The rate of the forward reaction
almond37 [142]

Answer:

The correct answer is "The reactions stop once equilibrum is achieved"

Explanation:

A system is said to have attained equilibrium when the rate of forward reaction is the same/equal to the rate of backward reaction.  The reaction below shows a chemical reaction that is at equilibrium

2N₂O₅ (aq) ⇄ 4NO₂ (aq) + O₂ (aq)

An equilibrium reaction is always a reversible reaction. <u>When the system is at equilibrium (when there is a balance), the concentration of the reactants and products do not change despite the fact that reaction does not stop</u>; what happens however is that the rate at which the reactant(s) are formed (backward reaction) will be equal to the rate at which the product(s) are formed (forward reaction).

From the explanation above, it can be deduced that "The reactions stop once equilibrum is achieved" is a misconception about a system in chemical equilibrium.

8 0
3 years ago
As __________ increases, the humidity of that area will __________. temperature; also increase dew; also increase rainfall; alwa
Nady [450]
Always increase temperature
4 0
3 years ago
A ball has m=10 kg and v=10 m/s. It has the same momentum as which of the following?
crimeas [40]

Answer:

Choice d. All three balls listed in choice a, b, and c have a momentum of 100\; \rm kg \cdot m \cdot s^{-1} each, same as that of the 10\; \rm kg ball moving at 10\; \rm m \cdot s^{-1}. Assumption: all four balls are moving in the same direction.

Explanation:

The momentum p of an object is equal to the product of its mass m and its velocity v.

Momentum of a 10\; \rm kg ball moving at 10\; \rm m \cdot s^{-1}:

p = m \cdot v = 10\; \rm kg \times 10\; \rm m \cdot s^{-1} = 100\; \rm kg \cdot m \cdot s^{-1}.

Similarly:

  • Momentum of the ball in choice a: 100 \; \rm kg \times 1\; \rm m \cdot s^{-1} = 100\; \rm kg \cdot m\cdot s^{-1}.
  • Momentum of the ball in choice b: 5 \; \rm kg \times 20\; \rm m \cdot s^{-1} = 100\; \rm kg \cdot m\cdot s^{-1}.
  • Momentum of the ball in choice c: 2 \; \rm kg \times 50\; \rm m \cdot s^{-1} = 100\; \rm kg \cdot m\cdot s^{-1}.

Hence the conclusion that these balls have the same momentum.

7 0
3 years ago
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