Yes. sound waves are produced by energy.
Answer:
T = 25 N
Explanation:
The question says that "A 25 n block is suspended by a wire from the ceiling vitamin the tension that appears in the wire
?"
Weight of the block, W = 25 N
Weight of a body acts in downward direction and tension acts in upward direction. It would mean that,
Tension = weight of the block
T = mg
T = 25 N
Hence, the tension in the wire is 25 N.
Answer:
1 millions times stronger
Answer:
Velocity(v) = frequency(f) × wavelength
f = 0.3165
Wavelength = 2×length(L)
L = 157cm
Convert the length in centimetres to metre = 1.57m
v = 2×1.57 × 0.3165
v = 0.99m/s
Approx. 1m/s
Explanation:
The velocity of a wave is the product of its frequency and it's wavelength. The frequency is already known. The wavelength is the distance between two successive wave crests which is formed by sloshing water back and forth in the bath tub. Sloshing water to one end of the tub will produce a wave crest first at that end then the other completing a cycle. The wavelength will be twice the length of the bath tub as it is the distance that both crests are formed.
Wave crest is the highest point of a wave, and in this case is where the water rises to a high point in the bath tub
Answer:
The voltage across the capacitor is 1.57 V.
Explanation:
Given that,
Number of turns = 10
Diameter = 1.0 cm
Resistance = 0.50 Ω
Capacitor = 1.0μ F
Magnetic field = 1.0 mT
We need to calculate the flux
Using formula of flux
![\phi=NBA](https://tex.z-dn.net/?f=%5Cphi%3DNBA)
Put the value into the formula
![\phi=10\times1.0\times10^{-3}\times\pi\times(0.5\times10^{-2})^2](https://tex.z-dn.net/?f=%5Cphi%3D10%5Ctimes1.0%5Ctimes10%5E%7B-3%7D%5Ctimes%5Cpi%5Ctimes%280.5%5Ctimes10%5E%7B-2%7D%29%5E2)
![\phi=7.85\times10^{-7}\ Tm^2](https://tex.z-dn.net/?f=%5Cphi%3D7.85%5Ctimes10%5E%7B-7%7D%5C%20Tm%5E2)
We need to calculate the induced emf
Using formula of induced emf
![\epsilon=\dfrac{d\phi}{dt}](https://tex.z-dn.net/?f=%5Cepsilon%3D%5Cdfrac%7Bd%5Cphi%7D%7Bdt%7D)
Put the value into the formula
![\epsilon=\dfrac{7.85\times10^{-7}}{dt}](https://tex.z-dn.net/?f=%5Cepsilon%3D%5Cdfrac%7B7.85%5Ctimes10%5E%7B-7%7D%7D%7Bdt%7D)
Put the value of emf from ohm's law
![\epsilon =IR](https://tex.z-dn.net/?f=%5Cepsilon%20%3DIR)
![IR=\dfrac{7.85\times10^{-7}}{dt}](https://tex.z-dn.net/?f=IR%3D%5Cdfrac%7B7.85%5Ctimes10%5E%7B-7%7D%7D%7Bdt%7D)
![Idt=\dfrac{7.85\times10^{-7}}{R}](https://tex.z-dn.net/?f=Idt%3D%5Cdfrac%7B7.85%5Ctimes10%5E%7B-7%7D%7D%7BR%7D)
![Idt=\dfrac{7.85\times10^{-7}}{0.50}](https://tex.z-dn.net/?f=Idt%3D%5Cdfrac%7B7.85%5Ctimes10%5E%7B-7%7D%7D%7B0.50%7D)
![Idt=0.00000157=1.57\times10^{-6}\ C](https://tex.z-dn.net/?f=Idt%3D0.00000157%3D1.57%5Ctimes10%5E%7B-6%7D%5C%20C)
We know that,
![Idt=dq](https://tex.z-dn.net/?f=Idt%3Ddq)
![dq=1.57\times10^{-6}\ C](https://tex.z-dn.net/?f=dq%3D1.57%5Ctimes10%5E%7B-6%7D%5C%20C)
We need to calculate the voltage across the capacitor
Using formula of charge
![dq=C dV](https://tex.z-dn.net/?f=dq%3DC%20dV)
![dV=\dfrac{dq}{C}](https://tex.z-dn.net/?f=dV%3D%5Cdfrac%7Bdq%7D%7BC%7D)
Put the value into the formula
![dV=\dfrac{1.57\times10^{-6}}{1.0\times10^{-6}}](https://tex.z-dn.net/?f=dV%3D%5Cdfrac%7B1.57%5Ctimes10%5E%7B-6%7D%7D%7B1.0%5Ctimes10%5E%7B-6%7D%7D)
![dV=1.57\ V](https://tex.z-dn.net/?f=dV%3D1.57%5C%20V)
Hence, The voltage across the capacitor is 1.57 V.