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Viktor [21]
3 years ago
13

A train is moving at a constant speed on a surface inclined upward at 15.0° with the horizontal and travels 300 meters in 5 seco

nds. Calculate the horizontal velocity of the train at the end of 3 seconds.
Physics
2 answers:
katovenus [111]3 years ago
6 0

Answer:

57,9 m/s

Explanation:

A train is moving at a constant speed on a surface inclined upward at 15.0° with the horizontal and travels 300 meters in 5 seconds. The horizontal velocity of the train at the end of 3 seconds is 100m/s.

The first formula we will use is:

v = d/t

300m ÷ 5s  = 60m/s

The last formula we will use is:

vh = v·cosx

60m/s·cos15.0°

60m/s · 0,965  = 57,9 m/s

Therefore, the answer is 57,9 m/s.

Hope this helped!

mr Goodwill [35]3 years ago
4 0
  • Answer:

<em>57,9 m/s</em>

  • Explanation:

<em>velocity formula</em>

<em>v = d/t</em>

<em>= 300m/5s</em>

<em>= 60m/s</em>

<em>horizontal velocity formula</em>

<em>vh = v·cosx</em>

<em>= 60m/s×cos15°</em>

<em>= 60m/s×0,965</em>

<em>= 57,9 m/s</em>

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