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Jobisdone [24]
3 years ago
5

Without Newton’s third law of motion, what would an object sitting on a table do?

Physics
2 answers:
Angelina_Jolie [31]3 years ago
8 0

Newton's third law: If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A. This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself.

boyakko [2]3 years ago
6 0

Without Newton's third law of motion, an object sitting on a table would continue sitting there, motionless, just we always see it do, and just as objects used to do before Newton ever developed his laws of motion.  

Getting the new law didn't change anything.  Just like everything else in Science, the new law was just a new description of how Nature works.  But it didn't change anything, because Nature doesn't care whether we understand how it works or not.

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Two planes, which are 37403740 miles apart, fly toward each other. their speeds differ by 35mph35â¢mph. if they pass each other
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A runner taking part in the 200 m dash must run around the end of a track that has a circular arc with a radius of curvature of
nlexa [21]

Answer:

a_c=1.44\ m/s^2

Explanation:

<u>Centripetal Acceleration</u>

It's the acceleration that an object has when traveling on a circular path to take into consideration the constant change of velocity it must have in order to keep going in the circular path.

Being v the tangent speed, and r the radius of curvature of the circle, then the centripetal acceleration is given by

\displaystyle a_c=\frac{v^2}{r}

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\displaystyle v=\frac{x}{t}=\frac{200\ m}{26.4\ s}

v=7.58\ m/s

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\displaystyle a_c=\frac{7.58^2}{40}=1.44\ m/s^2

\boxed{a_c=1.44\ m/s^2}

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Read 2 more answers
before colliding, the momentum of block A is +15.0 kg m/s. after, block A has a momentum -12.0 kg*m/s. what is the momentum of b
Helen [10]

Answer:

The momentum of block B = 27 Kg m/s

Explanation:

Given,

The initial momentum of block A, MU = 15 Kg m/s

The final momentum of block A, MV = -12 Kg m/s

Consider the block B is initially at rest.

Therefore, the initial momentum of block B, mu = 0

According to the laws of conservation of linear momentum, the momentum of the body before impact is equal to the momentum of the body after impact.

                               <em> MU + mu = MV + mv</em>

                                15  +  (0) = (-12) + mv

                                         mv = 15 + 12

                                              =  27 Kg m/s

Hence, the momentum of the block B after impact is, mv = 27 Kg m/s

3 0
2 years ago
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