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3 years ago

Without Newton’s third law of motion, what would an object sitting on a table do?

2 answers:

8 0

Newton's third law: If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A. This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself.

boyakko [2]3 years ago

6 0

Without Newton's third law of motion, an object sitting on a table would continue sitting there, motionless, just we always see it do, and just as objects used to do before Newton ever developed his laws of motion.

Getting the new law didn't change anything. Just like everything else in Science, the new law was just a new description of how Nature works. But it didn't change anything, because Nature doesn't care whether we understand how it works or not.

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A projectile is launched with an initial velocity of (40 m/s), at an angle of (30°) above

zlopas [31]

Answer:

330.5 m

Explanation:

In this case, the object is launched horizontally at 30° with an initial velocity of 40 m/s .

The maximum height will be calculated as;

$h=\frac{v^2_isin^2\alpha }{2g}$

where ∝ is the angle of launch = 30°

vi= initial launch velocity = 40 m/s

g= 10 m/s²

h= 40²*sin²40° / 2*10

h={1600*0.4132 }/ 20

h= 661.1/2 = 330.5 m

8 0

3 years ago

Compare the mass on Neptune (68.11) to the weight on Neptune (905.863). What is the difference? Why is there a difference?

Alchen [17]

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7 0

2 years ago

Suppose a car traveling at 8m/s is brought to rest in a distance of 20m.what is it's deceleration and time taken.

LiRa [457]

Answer:

Time - taken = 2.5 s

deceleration= -8 m/s²

Solution:

Given:

speed, v = 8 m/s

distance, d = 20m

To Find:

deacceleration = ?

As we know speed is defined as

v = d/t

plugging in the values

t = 20/ 8

t = 2.5s

Now from deceleration formula

a = - v/ t

a = - 20/ 2.5

a = - 8 m/s²

Thus, the time taken and acceleration is 2.5 s and -8 m/s²

respectively.

Learn more about deceleration here:

brainly.com/question/13354629

#SPJ4

7 0

2 years ago

A solid sphere of mass 8.6 kg, made of metal whose density is 3,400 kg/, hangs by a cord. When the sphere is immersed in a liqui

creativ13 [48]

Answer:

A. $1900 kg/m^3$

Explanation:

We are given that

$m=8.6 kg$

Density, $\rho_s=3400 kg/m^3$

Tension,T=38 N

We have to find the density of liquid.

$T=mg-\rho_l Vg$

$g=9.8 m/s^2$

Volume,V= $\frac{m}{\rho_s}$

$38=8.6\times 9.8-\rho_l\times \frac{8.6}{3400}\times 9.8$

$\rho_l\times \frac{8.6}{3400}\times 9.8=8.6\times 9.8-38$

$\rho_l=\frac{(8.6\times 9.8-38)\times 3400}{8.6\times 9.8}$

$\rho_l=1867kg/m^3\approx 1900 kg/m^3$

Option A is true.

4 0

3 years ago

While filming an intense action sequence for the next James Bond movie, a controlled explosion detonates 1.3 km away from the ac

brilliants [131]

To solve this problem we must basically resort to the kinematic equations of movement. For which speed is defined as the distance traveled in a given time. Mathematically this can be expressed as

$v = \frac{d}{t}$

Where

d = Distance

t = time

For which clearing the time we will have the expression

$t = \frac{d}{v}$

Since we have two 'fluids' in which the sound travels at different speeds we will have that for the rock the time elapsed to feel the explosion will be:

$t = \frac{1300m}{3000m/s}$