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Jobisdone [24]
3 years ago
5

Without Newton’s third law of motion, what would an object sitting on a table do?

Physics
2 answers:
Angelina_Jolie [31]3 years ago
8 0

Newton's third law: If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A. This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself.

boyakko [2]3 years ago
6 0

Without Newton's third law of motion, an object sitting on a table would continue sitting there, motionless, just we always see it do, and just as objects used to do before Newton ever developed his laws of motion.  

Getting the new law didn't change anything.  Just like everything else in Science, the new law was just a new description of how Nature works.  But it didn't change anything, because Nature doesn't care whether we understand how it works or not.

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Expressing Experimental Error If the accepted value of π is 3.1416, what are the fractional error and the percent error of the e
LUCKY_DIMON [66]

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1) Δx  = 0.16 m / s² ,   Δx = 9.72-9.8 = 0.08 m / s²

2)  e% = 1.63% , ,   e% = 0.816%

3)           1e% = 0.04

Explanation:

The fractional error in a quantity is the absolute error between the accepted value of the quantity and the percentage error is the fractional error per 100

In this case, it is not indicated which is the measured experimental value of pi, suppose that a value of 3.142 is measured

fractional error

                 e = (ax - ax_average) / x_average

                 e = (3.142 - 3.1416) / 3.1416

                 e = 1.27 10⁻⁴

the percentage error is

                 % = e 100

                 % = 1.27 10-4 100

                 % = 1.27 10⁻²%

1) Δx = 9.96-9.8 = 0.16 m / s²

            Δx = 9.72-9.8 = 0.08 m / s²

2) the percentage difference

 x = 9.96 m / s2

             e% = (9.96 - 9.80) / 9.80 100

             e% = 1.63%

x = 9.72 m / s2

             e% = (9.72 -9.80) / 9.80 100

              e% = 0.816%

3) the mean value is

                x_average = (x1 + x2) / 2

               x_average = (9.96 + 9.72) / 2

               x_average = 9.84 m / s2

               e% = (9.84 - 9.80) / 9.80 100

             1e% = 0.04

7 0
3 years ago
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