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vesna_86 [32]
2 years ago
13

In ΔMNO, m = 780 inches, o = 760 inches and ∠O=164°. Find all possible values of ∠M, to the nearest degree.

Mathematics
2 answers:
Mademuasel [1]2 years ago
4 0

Answer:

So the answer is both

180 and 328 (but it may or may not show you "not possible, if so, then you got it right)

Step-by-step explanation:

SinA/a= SinB/b

1. SinM/780 = Sin164/760

2. 780sin164/760 = 0.2828909704

3. M = sin^-1 (0.2828909704)= 16.4328229 or 16

Check for possibility

180-16= 164

164 + 16= 180 (not possible)

164 + 164= 328 (not possible)

exis [7]2 years ago
3 0

Answer:

just don't type anything there is no possible answer

Step-by-step explanation:

delta math

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The area of the hexagon 24a² -18 is equivalent to 6(4a² -3).

Option A is the correct answer.

<h3>What is a Hexagon ?</h3>

A polygon with 6 sides is called a Hexagon.

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The area of hexagon is given as

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Therefore the area of the hexagon 24a² -18 is equivalent to 6(4a² -3).

Option A is the correct answer.

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3 0
2 years ago
Solve the equation, <br>-3|6n-2|+5=8
Marianna [84]
Hey..... Nice to see you :)
Let me help you out.

-3|6n -2| + 5 = 8
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-3|6n -2| = 3
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No solutions.

Because absolute value cannot be less than 0.


I hope that's help !
5 0
3 years ago
. You draw a card from a well-shuffled deck of 52 cards. If you get a red card, you win nothing. If you get a spade, you win $4.
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7 0
3 years ago
GIVING BRAINLIEST OUT FOR WHOEVER IS CORRECT AND FAST!<br> All factors of 40, 41, 3526, and 1001.
mel-nik [20]

Answer:

Step-by-step explanation:

factors for

40=1,2,4,5,8,10,20,40

41=1,41  prime

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5 0
2 years ago
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One sign lights up every 10 seconds. One sign lights up every 12 seconds. If they have just lit up at the same time, how many se
andrew11 [14]

Answer:

It will take 60 seconds for the signs to light up at the same time again.

Step-by-step explanation:

Given:

One sign lights up every 10 seconds

One sign lights up every 12 seconds

They have just lit up at the same time.

To find in how many seconds will it take for the signs to light up at the same time again.

Solution:

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To find the LCM, we will list the multiples of each and check the least common multiple.

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7 0
3 years ago
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