Im assuming the height is dropped so that it is the halfway point. this would then make the base 5cm, with a height of 12cm. if that is the case then the answer should be 13
{6y^3+2y^2}{10y^2}= 10y 2 6y 3 +2y 2 =start fraction, 6, y, cubed, plus, 2, y, squared, divided by, 10, y, squared, end fracti
malfutka [58]
Answer:
y=0
Step-by-step explanation:
Definition:An expression is undefined at the value(s) at which the denominator equals zero.
We are to determine the value of y that makes the expression undefined.
![\dfrac{6y^3+2y^2}{10y^2}](https://tex.z-dn.net/?f=%5Cdfrac%7B6y%5E3%2B2y%5E2%7D%7B10y%5E2%7D)
We equate the denominator to zero and solve for y.
![10y^2=0\\y^2=0\\y=0](https://tex.z-dn.net/?f=10y%5E2%3D0%5C%5Cy%5E2%3D0%5C%5Cy%3D0)
Therefore, at y=0, the given expression is undefined.
Answer:
Released oxygen mass: 15.92 kg
Step-by-step explanation:
ideal gas law : P*V=nRT
P:pressure
V:volume
T:temperature
n:number of moles of gas
n [mol] = m [g] /M [u]
m : masa
M: masa molar = 15,999 u (oxygen)
R: ideal gas constant = 8.314472 cm^3 *MPa/K*mol =
grados K = °C + 273.15
P1*V*M/R*T = m1
P2*V*M/R*T = m2
masa released : m1-m2 = (P1-P2) * V*M/R*T
m2-m1 = 200 * 10^-3 MPa * 12 * 10^6 cm^3 * 15.999 u / 8.314472 (cm^3 * MPa/K *mol) * 290. 15 K
m2-m1= 38 397.6 * 10^3 u*mol / 2412.44 = 15916.5 g = 15.9165 kg
Answer:
39
Step-by-step explanation:
quarters are worth $.25. just divide 9.75 by .25 and you get your answer.
9.75 ÷ .25 = 39
It’s just a square that’s displaced. 12*9=108