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3 years ago

Which shape has six square, flat sides that are equal in size?

Mathematics

1 answer:

Firlakuza [10]3 years ago

8 0

Answer: cube

Step-by-step explanation:

Think of a box .... it has 4 sides, a top, and a bottom = 6 total sides

Which of the following statements are true for a rhombus? It has two pairs of parallel sides. It has two pairs of equal sides. It has only two pairs of equal sides. Two of its angles are at right angles. Its diagonals bisect each other at right angles. Its diagonals are equal and perpendicular. It has all its sides of equal lengths. It is a parallelogram. It is a quadrilateral. It can be a square. It is a square.

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Can someone please help with these please!!

ryzh [129]

Answer:

27.57

is the Mean

20 is the mode (most repetative)

26 is the median (the number in the middle when in order)

Step-by-step explanation:

SO they look better by using their Mean Score 27.57 Points

5 0

3 years ago

Read 2 more answers

Which statement is correct?

Arisa [49]

Answer:

$2.06 \times 10^-^2 = 206$

$1.88 \times 10^-^1 = 18.8$

$206 \times 18.8 = 3,872.8$

$7.69 \times 10^-^2 = 769$

$2.3 \times 10^-^5 = 230,000$

$=\frac{769}{230000}$

= 0.00334

therefore,

3,872.80 > 0.00334

Step-by-step explanation:

Which statement is correct?

(2.06x102x1.88 x 10-1) <7.69x 10

2.3x10-5

(2.06 x 10-2)(1.88 x 10-1) 7.69x 10-

2.3x10-5

7.69 x 10"

(2.06 x 10-2x1.88x10-)>

2.3x10-5

(2.06x 10-2X(1.88x 10-1)-7.69x104

2.3x10-5

Given that;

$2.06 \times 10^-^2 = 206$

$1.88 \times 10^-^1 = 18.8$

$206 \times 18.8 = 3,872.8$

$7.69 \times 10^-^2 = 769$

$2.3 \times 10^-^5 = 230,000$

$=\frac{769}{230000}$

= 0.00334

therefore,

3,872.80 > 0.00334

7 0

3 years ago

dana is flying a kite whose string is 65 meters long and makes a 70 degree angle with the ground. How far is the kite above the

SSSSS [86.1K]

Here you would want to use the sine function, since it’s making a triangle with the ground, and length of the string, the height to the kite. This can be found by 65sin(70°) which is ≈ 61.08 meters

3 0

3 years ago

It is estimated that the population of the world is increasing at an average rate of 1.09%. The population was about 7,632,819,3

morpeh [17]

Answer:

The equation that represents the population after T years is

$P_{t} = 7,632,819,325 [1 +\frac{1.09}{100} ]^{T}$

Step-by-step explanation:

Population in the year 2018 ( P )= 7,632,819,325

Rate of increase R = 1.09 %

The population after T years is given by the formula

$P_{t} = P [1 +\frac{R}{100} ]^{T}$ -------- (1)

Where P = population in 2018

R = rate of increase

T = time period

Put the values of P & R in above equation we get

$P_{t} = 7,632,819,325 [1 +\frac{1.09}{100} ]^{T}$

This is the equation that represents the population after T years.

6 0

3 years ago

The average monthly rent for a? 1000-sq-ft apartment in a major metropolitan area from 1998 through 2005 can be approximated by

Lunna [17]

Answer:

t = 1.107

Step-by-step explanation:

Finding the solution using derivatives involves finding the lower zero of the quadratic that is the second derivative of the given function. That second derivative will be ...

f''(t) = 12(1.6714)t^2 -6(22.45)t +2(62.27)

= 20.0568t^2 -134.7t +124.54

= 20.0568(t -3.35796)² -101.619 . . . . rewrite to vertex form

Then f''(t) = 0 when ...

t ≈ 3.35796 -√(101.619/20.0568) ≈ 1.10706

The solution is perhaps more easily found using a graphing calculator to find the peak of the first derivative. (See attached.) It tells us ...

t ≈ 1.107

1.1 years after the beginning of 1998 is about 1.2 months into 1999.

Rents were increasing most rapidly in early February of 1999.

8 0

3 years ago