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3 years ago

7

Which shape has six square, flat sides that are equal in size?

1 answer:

Firlakuza [10]3 years ago

8 0

Answer: cube

Step-by-step explanation:

Think of a box .... it has 4 sides, a top, and a bottom = 6 total sides

Which of the following statements are true for a rhombus? It has two pairs of parallel sides. It has two pairs of equal sides. It has only two pairs of equal sides. Two of its angles are at right angles. Its diagonals bisect each other at right angles. Its diagonals are equal and perpendicular. It has all its sides of equal lengths. It is a parallelogram. It is a quadrilateral. It can be a square. It is a square.

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What's the slope intercept form for this graphed line.

kicyunya [14]

The slope is seven boxes.

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4 years ago

Are the ratios 8:7 and 2:1 equivalent?<br> yes<br> no

padilas [110]

Answer:

No

Step-by-step explanation:

It would have to be something like

8:4 and 2:1

or 8:7 and 16:14

6 0

3 years ago

Read 2 more answers

Can y’all pls help me find the area of shaded region. pls no links. it’s due today 4/19

AveGali [126]

Area of a Trapezium

The trapezium has two parallel sides and two non-parallel sides

Since sides of lengths 7, 5 are parallel and perpendicular to the side of length 4. Thus the trapezium has bases b1=7, b2=5, and height h=4.

The formula to calculate the area of a trapezium is:

$A=\frac{b1+b2}{2}\cdot h$

Substituting:

$A=\frac{7+5}{2}\cdot4=\frac{12}{2}\cdot4=24$

The area of the shaded region is 24 square units

5 0

2 years ago

Question is in the picture. Please answer

morpeh [17]

Answer:

$tan(A) = \frac{4}{3}$

Step-by-step explanation:

Here we see tan(B) has opposite side of 12 and adjacent of 9

using the formula:

$tan(A) = \frac{opposite }{adjacent}$

$tan(A) = \frac{12}{9}$

$tan(A) = \frac{4}{3}$

6 0

3 years ago

Read 2 more answers

The probability that the noise level of a wide-band amplifier will exceed 2 dB is 0.05 independently of every other amplifier. C

snow_lady [41]

Answer:

0.980

Step-by-step explanation:

The probability that the noise level of a wide-band amplifier will exceed 2 dB is 0.05

So, probability of success = 0.05

Probability of failure = 1-0.05=0.95

There are 12 amplifiers

We are supposed to find the probability that at most two will exceed 2dB.

We will use binomial distribution

Formula : $P(X=r)=^nC_r p^r q ^{n-r}$

p = 0.05

q = 0.95

n = 12

We are supposed to find the probability that at most two will exceed 2dB.

So, $P(X\leq 2)=P(X=0)+P(X=1)+P(X=2)$

$P(X\leq 2)=^{12}C_0 P(0.05)^0 (0.95)^{12-0}+^{12}C_1 P(0.05)^1(0.95)^{12-1}+^{12}C_2 P(0.05)^2 (0.95)^{12-2}$

$P(X\leq 2)=\frac{12!}{0!(12-0)!} (0.05)^0 (0.95)^{12-0}+\frac{12!}{1!(12-1)!}(0.05)^1(0.95)^{12-1}+\frac{12!}{2!(12-2)!} (0.05)^2 (0.95)^{12-2}$

$P(X\leq 2)=0.980$

Hence the probability that at most two will exceed 2dB is 0.980

7 0

3 years ago