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Nikolay [14]
3 years ago
15

Solve for the distance between the points (4, 4) and (1, -3).

Mathematics
1 answer:
antoniya [11.8K]3 years ago
7 0
I think the distance is 3/7. This is because 4 minus 1 is 3 (they are both in the same quadrant, so u subtract/are both positive too). -3 is three away from zero and 4 is 4 away from zero. If you add those together, you get those points (also, u add numbers in different quadrants together). Therefore, the distance is 3/7. Hope this helps!
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Step-by-step explanation:

looking at the equation you can see it is in y=mx+b form. this means that the coefficient next to the x is the slope

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Read 2 more answers
The angle θ lies in Quadrant II .
Andreyy89

let's keep in mind that, in the II Quadrant, cosine is negative and sine, is positive.

cosine is adjacent/hypotenuse, however the hypotenuse is simply a radius unit, and thus is never negative, so in the -(2/3) the negative must be the numerator, -2.


\bf cos(\theta )=\cfrac{\stackrel{adjacent}{-2}}{\stackrel{hypotenuse}{3}}\impliedby \textit{let's find the \underline{opposite side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{3^2-(-2)^2}=b\implies \pm\sqrt{5}=b\implies \stackrel{\textit{II Quadrant}}{+\sqrt{5}=b}~\hfill tan(\theta )=\cfrac{\stackrel{opposite}{\sqrt{5}}}{\stackrel{adjacent}{-2}} \\\\\\ ~\hspace{34em}

6 0
4 years ago
You randomly choose a marble from a jar. The jar contains 3 red marbles, 10 blue marbles, 8 green marbles, and 4 yellow marbles.
anastassius [24]

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Step-by-step explanation:

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4 years ago
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