The answer is B. fight disease
The ileum has <span>plicae circulares</span>, villi and microvilli, that are folds and projections of the mucosa layer of the ileum, that increase the surface area of food absorption. The mucosa and the submucosa of the stomach have inner folds called rugae that increase the surface areas in which food is digested by enzymes.
Plants have root hairs in their tap roots that also increase the surface area for which they absorb water and nutrient from the soil. Fibrous roots have a mesh-like a network that also increases the surface area for increased absorption.
Answer:
kilogram
Explanation:
it's not an option but that's the right answer
Answer:
Options (1), (2), (3) and (4)
Explanation:
Mid oceanic ridge is the region along the spreading of the sea floor occurs. Along this ridge, the magma come out to the surface, and lava forms<u> pillow shaped rocks such as pillow basalt</u>. Basalt is the dominant rock type in the oceanic crust.
There occurs<u> striped patterns that are oriented parallel mid oceanic ridge</u>, and this strips depicts the magnetic field of the earth, and it keeps on changing on each eruption of this magma beneath the ocean long this ridge.
The mid oceanic ridge suggests the <u>spreading of the sea floor</u> and the rocks present at this ridge are younger than the rocks that are away from the ridge.
This rocks are comprised of the <u>molten iron material</u> that are present in the mantle and suggest the magnetic field of the earth during the time of eruptions.
Hence, the correct answers are options (1), (2), (3) and (4).
Answer:
The population is not following the Hardy-Weinberg equilibrium.
Explanation:
Hardy-Weinberg proposed that the population will remain in the equilibrium if they are not affected with the external natural force like genetic drift, mutation and many others. The gene pool of a population will remain in equilibrium state for generations.
The mathematical expression for the Hardy-Weinberg are
Genotypic frequency is p²+q²+2pq=1
Allele frequency is p+q=1
where p-dominant allele,
q-recessive allele
Therefore,calculating expected frequency of allele q,
q² (recessive genotype)- q²+2pq/1000
= 22+188/1000
=210/1000
= 0.21
q= 0.45
Calculating expected frequency of allele p,
Using p+q=1
p=1-q
p= 0.55 (expected)
Calculating observed value of frequency of p,
p²= p²+2pq/1000
= 790+188/1000
= 978/1000
= 0.978
p = 0.988 (observed)
Since the expected frequency does not match the observed frequency therefore the population is not under the Hardy-Weinberg equilibrium and the gene pool is disturbed.
