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ANEK [815]
3 years ago
9

A phone company needs to know how tall a cell tower is, so it decides to use a 2 m pole and shadows cast by the sun, as shown in

the diagram. Both shadows end at point B. What is the height of the tower?
A. 30 m
B. 32 m
C. 36 m
D. 40 m

Mathematics
2 answers:
Wewaii [24]3 years ago
6 0
(cell tower)/((45 +3) m) = (2 m)/(3 m)
(cell tower) = (48 m)(2/3) = 32 m

B. 32 m . . . . . is the appropriate selection
motikmotik3 years ago
4 0

Answer:

B. 32 m

Step-by-step explanation:

Here we can join the top of the cell phone tower to the point B. Similarly, we can join the pole top to the point B.

We will get a two similar triangles.

The ratio of similar triangles are in proportion.

Let's take "x" be height of the cell phone tower.

Cell phone tower          Cell phone tower shadow

-------------------------  =  ------------------------------------

Pole                                    Pole shadow

x/2 = (45 + 3)/3

x/2 = 48/3

x/2 = 16

Multiplying both sides, we get

x = 2*16

x = 32 meters

Therefore, the height of the cell phone tower is 32 meters.

It is B. 32 m

Hope this will helpful.

Thank you.

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5 0
3 years ago
Find all the zeros of the equation<br> -3x^4 + 27x^2 + 1200 = 0
guajiro [1.7K]

Answer:

\displaystyle x=-5,\ x=5,\ x=4i,\ x=-4i

Step-by-step explanation:

Biquadratic Equation

It's a fourth-degree equation where the terms of degree 1 and 3 are missing. It can be solved for the variable squared as if it was a second-degree equation, and then take the square root of the results

Our equation is

\displaystyle -3x^4+27x^2+1200=0

If we call y=x^2, our equation becomes a second-degree equation

\displaystyle -3y^2+27y+1200=0

Dividing by -3

\displaystyle y^2-9y-400=0

Factoring

\displaystyle (y-25)(y+16)=0

It leads to these solutions

\displaystyle y=25\ ,\ y=-16

Taking back the change of variable, we have for the first solution

\displaystyle x^2=25\Rightarrow x=-5,x=5

Now for the second solution, we get imaginary (complex) values

\displaystyle x^2=-16\Rightarrow x=4i,\ x=-4i

Summarizing, the four solutions for x are

\displaystyle x=-5,\ x=5,\ x=4i,\ x=-4i

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