Answer:
After the extended period of time, Pete would have typed 6400 words.
Step-by-step explanation:
Given the data in the question;
In the same time;
number typed word of Pete = 80
type word of Ralph = 50
After a period time;
number of typed word of Pete = ?
number of typed word of Ralph = 4000
so, let x represent the number of typed word by Pete after an extended period.
so
80 words = 50 words
x words = 4000 words
we cross multiply
x × 50 = 4000 × 80
x = ( 4000 × 80 ) / 50
x = 320000 / 80
x = 6400
Therefore, After the extended period of time, Pete would have typed 6400 words.
Answer:
The probability of founding exactly one defective item in the sample is P=0.275.
The mean and variance of defective components in the sample are:
Step-by-step explanation:
In the case we have a lot with 3 defectives components, the proportion of defectives is:
a) The number of defectives components in the 5-components sample will follow a binomial distribution B(5,0.075).
The probability of having one defective in the sample is:
b) The mean and variance of defective components in the sample is:
The Chebyschev's inequality established:
2x^3(x+7)(x-7)
Thats the answer for your question!
Answer:
Marcela can take up to 13 units.
Step-by-step explanation:
In order to find the number of units that Marcela can take for her college classes, we can set up an inequality and solve for the variable. Since each unit costs $105, we can say that 105u ≤ 1365 where u = the number of units. The number of units multiplied by the cost per unit, must be less than or equal to $1,365. In order to solve for 'u', we can use inverse (opposite) operations and get rid of the coefficient by dividing both sides of the inequality by 105. 1365÷105 = 13. So, the number of units that Marcela can take must be less than or equal to 13 units.
1/5 divided by 6
6 = 6/1
When dividing fractions, we follow a rule called "Keep, change, flip."
It then becomes: 1/5 * 1/6 = 1/30
1 fifth divided by 6 equals 1/30
