Answer:
2.21 N
Explanation:
The force in this case is the total mass multiplied by the acceleration due to gravity. You are not asked for the solution to be in terms of the torque which is the usual way to solve these problems. That's why you are not given where the fulcrum is.
The fulcrum feels F1 + F2 + 34 * 980
F2 = 141.7 * 980 = 138866
F1 = 50.3 * 980 = 49294
Ruler = 34 * 980= 33320
Total Force = 221480 The units here are dynes
I just saw in the middle of the question that g = 9.80
So the answer becomes 221480 / 1000 = 221.48 because we needed kg
And that answer becomes 221.48/100 2.21 because the force of gravity should be 9.8 not 980
The total force exerted on the fulcrum is
Answer:
The distance is 0.9681 m.
Explanation:
Given that,
Length = 0.95 m
Mass of block = 7.9 kg
Stretches spring length = 1.06 m
another mass = 1.3 kg
Magnitude of restoring force acting in the spring equal to the magnitude of applied force
We need to calculate the spring constant
Using Hook's law,
Put the value into the formula
Put the value into the formula
We need to calculate the distance
Using formula of spring constant
Put the value into the formula
We need to calculate the total distance
Using formula of distance
Hence, The distance is 0.9681 m.
"The potential on the surface of a conductor is always zero."
This statement is false. A good number of times we define a point's potential to be the amount of work that must be done to move 1 coulomb of charge from infinitely far away to that point. So if, let's say, the conductor had a net positive charge, then you would need to do a net positive amount of work to move 1 coulomb of charge from infinitely far away to any point on the conductor's surface. We have just provided a case for which the potential on the surface of the conductor is not 0.
Answer:
Gauge pressure rise = 292 Pa
Explanation:
We are given;
Diameter of the water droplet is d = 2mm = 0.002m
Radius = 0.002/2 = 0.001
Surface tension; σ = 73 mNm = 73 x 10^(-3)m
So we have to find the pressure rise.
Now, pressure rise is given by the formula ;
ΔP = P_inside - P_atmosphere = 4σ/r
Where r is radius.
Thus, plugging in the relevant values, we have;
ΔP = (4 x 73 x 10^(-3))/0.001 = 292 pa