-- more mass involved
-- less distance between the two objects
Answer:
The average acceleration during the 6.0 s interval was -27 m/s².
Explanation:
Hi there!
The average acceleration is defined as the change in velocity over time:
a = Δv/t
Where:
a = acceleration.
Δv = change in velocity = final velocity - initial velocity
t = elapsed time
The change in velocity will be:
Δv = final velocity - initial velocity
Δv = -74 m/s - 87 m/s = -161 m/s
(notice the negative sign of the velocity that is in opposite direction to the direction considered positive)
Then the average acceleration will be:
a = Δv/t
a = -161 m/s / 6.0 s
a = -27 m/s²
The average acceleration during the 6.0 s interval was -27 m/s².
Answer:
521.8 V
Explanation:
The RMS value of the voltage of an AC signal is given by
where
is the peak voltage, which corresponds to the amplitude of the AC waveform
In this problem, we know the RMS voltage
Therefore, we can re-arrange the previous equation to find the peak voltage (the amplitude of the waveform):
Jsbdbansnduxjxhxjxjjxjxjxjxdjx
When two atoms of the same nonmetal react,they form what we know today as a diatomic molecule.
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