Convenience items like liquid egg are a lot more expensive? True Or False

How many ase certifications are there for automotive technicians?

romanna [79]

Answer:

There are 50 ASE certification tests, covering almost every imaginable aspect of the automotive repair and service industry.

Explanation:

yww <33

5 0

3 years ago

The explosion of a hydrogen bomb can be approximated by a fireball with a temperature of 7200 K, according to a report published

Iteru [2.4K]

Answer:

a

The rate of radiation of the energy is $E_r = 1.523747635*10^9 W/m^2$

b

The irradiation is $G =46.177\ kW/m^2$

c

The amount of energy absorbed is $E_B = 461.772 KJ$

d

The oak Tree would catch fire because the temperature of the blast(7200 K) is higher than the flammability limit (650 K) of the oak tree and secondly the thickness is very small

Explanation:

From the question we are told that

The temperature is $T = 7200K$

The diameter of the ball is $d = 1.5 km = 1.5 *1000 = 1500m$

Hence the radius = $= \frac{1500}{2} = 750m$

The total energy radiated can be mathematically represented as

$E = \sigma A T^4$

Where $\sigma$ is the Stefan-Boltzmann constant $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 5.67*10^{-8} W \ \cdot m^{-2} K^{-4}$

A is the area of a sphere = $\pi d^2 = 3.142 * 1500^2 = 7.069500 *10 ^6\ m^2$

Substituting values we have

$E = 5,67*10^{-8} * 7.069500*10^6 * 7200^4$

$=1.077*10^{15} W$

Now the state of the energy is mathematically represented as

$Rate \ of \ energy \ radiation (E_r)= \frac{E}{A} = \sigma T^4$

$= 5.67*10^{-8} * 7200^2$

$= 1.523747635*10^9 W/m^2$

A sketch illustrating the b part of the question is shown on the first uploaded image

looking at the height at which the blast occurs(16km) as compared to the height of the wall we notice that the height of the wall is negligibly small

from the diagram x can be calculated as follows

$x = \sqrt{40^2 + 16^2}$

$= 43.0813 Km$

This value of x represents the radius of the blast(assuming it is spherical ) when it is at that wall

Now the irradiation G is mathematically represented as

$G = \frac{E}{4 \pi r^2}$

Here r = 43.0813 Km = 43.0813 × 1000 = 43081.3 m

$G= \frac{1.077*10^15}{4 \pi (431081.3^2)}$

$G =46.177\ kW/m^2$

Generally the amount of energy absorbed can be mathematically represented as

$Amount \ of \ energy \ absorbed \ (E_B ) = G * t$

Where t is the time taken

Therefore $E_B = 46.177 *10 = 461.77 KJ$

6 0

3 years ago

Two Technicians are discussing the Battery Council

nexus9112 [7]

Answer:

Technician A

Explanation:

The Battery Council International (BCI) battery group numbers is an industry standard for batteries that indicate two important this;

Physical size of a car battery which are; height , width and length.
Polarity on the battery which is the location of the positive and negative battery posts

For example : a group 24 battery or a type 27 marine battery are battery group numbers that define the physical dimensions of a battery case. These numbers are important because car owners and manufacturers use the numbers to match vehicle power requirements with the alternators .A mismatch of the battery and the alternator can cause the vehicle's alternator to overheat leading to a short life span.

Technician A statement is correct.

3 0

3 years ago

The high electrical conductivity of copper is an important design factor that helps improve the energy efficiency of electric mo

ludmilkaskok [199]

Answer:

B

Explanation:

This is a two sample t-test and not a matched pair t-test

null hypothesis(H0) will be that mean energy consumed by copper rotor motors is greater than or equal to mean energy consumed by aluminium rotor motors

alternate hypothesis(H1) will be that mean energy consumed by copper rotor motors is less than or equal to mean energy consumed by aluminium rotor motors.

So, option D is rejected

The hypothesis will not compare mean of differences of values of energy consumed by copper rotor motor and aluminium rotor motor.

Option A and C are also rejected

5 0

3 years ago

Create a package named one_dimensional_array and write a class that completes the following "OneDimensionalArrays" class. You wi

yan [13]

Answer:

The filled in codes are

1) private static int[] arr;

2) int arr[] = new int[size_of_array];

int increment = 100;

for (int i = 0; i < size_of_array; i++) {

arr[i] = increment * i;

}

return arr;

3) for (int i = 0; i < myArray.length; i++) {

System.out.println(myArray[i]);

4) OneDimensionalArrays result = new OneDimensionalArrays();

result.createIntegers(num);

result.printArray(arr);

Explanation:

Create a package named one_dimensional_array and write a class that completes the following "OneDimensionalArrays" class. You will complete the class by filling in code wherever you see the comment:

//******* FILL IN CODE *********

import java.util.Scanner;

public class OneDimensionalArrays {

int[] createIntegers(int size_of_array)

{

//******* FILL IN CODE *********

// Your code will create an array of ints as large as specified in size_of_array

// Fill the array in with the values: 0, 100, 200, 300, ....

// Return the array that you just created

}

void printArray(int[] myArray)

{

//******* FILL IN CODE *********

// Print out your array with one number per line. Get the size of the

// array from the "myArray" parameter (no hard coding the size)

}

public static void main(String[] args) {

Scanner keyboard = new Scanner(System.in);

System.out.println("Enter size of array to create: ");

int num = keyboard.nextInt();

//******* FILL IN CODE *********

// Construct an instance of the OneDimensionalArrays class

// Using this object instance, call createIntegers to create

// an array of integers. Don't forget to save the results

// Then call the printArray method to print out the contents

// of your array.

}

Completed Code when filled in looks this way below:

import java.util.Scanner;

public class OneDimensionalArrays {

private static int[] arr;

int[] createIntegers(int size_of_array) {

int arr[] = new int[size_of_array];

int increment = 100;

for (int i = 0; i < size_of_array; i++) {

arr[i] = increment * i;

}

return arr;

}

void printArray(int[] myArray) {

for (int i = 0; i < myArray.length; i++) {

System.out.println(myArray[i]);

}

public static void main(String[] args) {

Scanner keyboard = new Scanner(System.in);

System.out.println("Enter size of array to create: ");

int num = keyboard.nextInt();

OneDimensionalArrays result = new OneDimensionalArrays();

result.createIntegers(num);

result.printArray(arr);

}

7 0

3 years ago