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Sonbull [250]
3 years ago
13

Answer true or false 3.Individual people decide what will be produced in a command oconomy

Engineering
2 answers:
Pie3 years ago
7 0

Answer:

False

Explanation:

The government decides the productions.

Leto [7]3 years ago
3 0
False

In a command economy, the government controls major aspects of economic production. The government decides the means of production and owns the industries that produce goods and services for the public. The government prices and produces goods and services that it thinks benefits the people.
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A lake has a carrying capacity of 10,000 fish. At the current level of fishing, 2,000 fish per year are taken with the catch uni
arlik [135]

Answer:

The population size would be p' = 5000

The yield would be    MaxYield = 2082 \ fishes \ per \ year

Explanation:

So in this problem we are going to be examining the application of a  population dynamics a fishing pond and stock fishing and objective would be to obtain the maximum sustainable yield and and the population of the fish at the obtained maximum sustainable yield,  so basically we would be applying an engineering solution to fishing

 

    So the current  yield which is mathematically represented as

                               \frac{dN}{dt} =   \frac{2000}{1 \ year }

 Where dN is the change in the number of fish

            and dt is the change in time

So in order to obtain the solution we need to obtain the  rate of growth

    For this we would be making use of the growth rate equation which is

                                      r = \frac{[\frac{dN}{dt}] }{N[1-\frac{N}{K} ]}

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          and  K is the carrying capacity which is given as 10,000 fishes

             r is the growth rate

        Substituting these values into the equation

                              r = \frac{[\frac{2000}{year}] }{4000[1-\frac{4000}{10,000} ]}  =0.833

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                      Max Yield  = \frac{rK}{4} = \frac{(10,000)(0.833)}{4} = 2082 \ fishes \ per \ year

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                          p' = \frac{K}{2}  = \frac{10,000}{2}  = 5000\ fishes          

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