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3 years ago

A cheetah can run 56 miles per hour. At that rate, a cheetah can run 27 miles in 15 minutes.

Mathematics

1 answer:

-Dominant- [34]3 years ago

4 0

Answer:

false, they can run 14 miles in 15 minutes

Step-by-step explanation:

56 divide by 4 = 14

60 divided by 15 = 4

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The number in a fraction that tells how many equal parts are in the hall or in a group

Paul [167]

I think the answer is "the denominator"

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3 years ago

Which value must be added to the expression x2 + x to make it a perfect-square trinomial? One-fourth One-half 1 4

SVEN [57.7K]

Answer:

$\frac{1}{4}$

Step-by-step explanation:

Given

x² + x

To complete the square

add ( half the coefficient of the x- term )² to x² + x

x² + 2( $\frac{1}{2}$ )x + ( $\frac{1}{2}$ )² = x² + x + $\frac{1}{4}$

= (x + $\frac{1}{2}$ )² ← perfect square

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3 years ago

Read 2 more answers

Olivia has budgeted 40% of her savings for a new phone. If she had $500 in her savings account, how much can she spend on the ph

rodikova [14]

Answer:200$

Step-by-step explanation:

4 0

3 years ago

ILL GIVE BRAINLIEST PLS HELP

yan [13]

Answer:

1/5

Step-by-step explanation:

The stick has a length of 5 units

The stick is broken at two points chosen at random

First break: the probability that you get a piece that is 1 unit or longer than 1 units= 1/5.

Second break, the probability that you get a piece that is 1 unit or longer than 1 units is 1/5.

Therefore,

The total probability =probability of first break * probability of second break * original stick unit

=1/5 * 1/5 * 5

= 1/25 *5

=5/25

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4 0

3 years ago

Given that sin theta = 1/4, 0→theta→π/2, what<br>. what is the exact value of cos 8?

natali 33 [55]

<h3>Answer: Choice B $\frac{\sqrt{15}}{4}$ </h3>

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Work Shown:

Angle theta is between 0 and pi/2, so this angle is in quadrant Q1.

Square both sides of the given equation

$\sin \theta = \frac{1}{4}\\\\\sin^2 \theta = \left(\frac{1}{4}\right)^2\\\\\sin^2 \theta = \frac{1}{16}$

Then use the pythagorean trig identity to get

$\sin^2 \theta + \cos^2 \theta = 1\\\\\cos^2 \theta = 1-\sin^2 \theta\\\\\cos \theta = \sqrt{1-\sin^2 \theta} \ \ \ \text{cosine is positive in Q1}\\\\\cos \theta = \sqrt{1-\frac{1}{16}}\\\\\cos \theta = \sqrt{\frac{16}{16}-\frac{1}{16}}\\\\\cos \theta = \sqrt{\frac{16-1}{16}}\\\\\cos \theta = \sqrt{\frac{15}{16}}\\\\\cos \theta = \frac{\sqrt{15}}{\sqrt{16}}\\\\\cos \theta = \frac{\sqrt{15}}{4}\\\\$

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3 years ago