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Y_Kistochka [10]
3 years ago
8

3)

Mathematics
1 answer:
Leni [432]3 years ago
6 0

\longrightarrow{\green{  x\:=\:12}} 

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

(x - 9) \frac{2}{3}  = 2

➺ \: (x - 9) = 2 \times  \frac{3}{2}

➺ \: x =  3 + 9

➺ \: x = 12

Therefore, the value of x is 12.

\large\mathfrak{{\pmb{\underline{\blue{To\:verify}}{\blue{:}}}}}

(x - 9) \frac{2}{ 3}  = 2

➺ \: (12 - 9) \frac{2}{3}  = 2

➺ \: 3 \times  \frac{2}{3}  = 2

➺ \: 2 = 2

➺ \: L.H.S.=R. H. S

Hence verified.

\huge\bf\purple{*Mystique 35♡༉}

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Solve.<br> X = -7<br> 4x - 4y = 12<br> (x,y)
Fynjy0 [20]

Answer:

(-7, -10)

x=-7\\y=-10

Step-by-step explanation:

4x-4y=12

Substitute x for -7.

4(-7)-4y=12

Multiply 4 by -7.

-28-4y=12

Add 28 on both sides.

-4y=40

Divide -4 on both sides.

y=-10

4 0
3 years ago
Explain how to use a pattern to find 35.6 ÷10 to the second power
Ad libitum [116K]
10 to the 2nd power only means 10x10=100
35.6/100=0.256
35.6/10x10=0.256
3 0
3 years ago
Read 2 more answers
If u = 2i - j; v= -5i + 4j and w = j find 4u (v -w).
Sedaia [141]

Answer:

-40

Explanation:

Given

u = 2i - j; v= -5i + 4j and w = j

Required

4u(v-w)

4u = 4(2i) = 8i

v - w = -5i + 4j - j

v - w = -5i + 3j

Substitute

4u(v-w)

= 8i(-5i+3j)

= -40(i*i) [since i*i = 1]

= -40

Hence the required solution is -40

5 0
2 years ago
jeremy has a job packing boxes in a warehouse. Jeremy must pack 20 boxes each day that he works to meet quota. He can pack 4 box
eimsori [14]

Answer:

Yes he has enough boxes to meet quota.

Step-by-step explanation:

4 x 8 = 32 This is over what he is requried to meet quota he is at quota.

7 0
3 years ago
Read 2 more answers
Solve the following equations;-<br><br> x - 9 /√x + 3 =1
fgiga [73]

Answer:

13 , 6.

Step-by-step explanation:

A equation is given to us and we need to find out the value of x . The given equation to us is ,

\sf\implies \dfrac{ x -9}{\sqrt{x+3}}= 1

Cross multiply ,

\sf\implies x - 9 =\sqrt{ x +3}

Squaring both sides ,

\sf\implies (x - 9)^2 = x + 3

Simplify the whole square ,

\sf\implies x^2+9^2-2.9.x = x +3 \\

\sf\implies x^2+81 - 18x = x -3

Add 3 and subtract x on both sides ,

\sf\implies x^2 -18x-x +81-3=0

Simplify ,

\sf\implies x^2 -19x +78=0

Split the middle term of the quadratic equation,

\sf\implies x^2-13x-6x+78=0

Take out common ,

\sf\implies x( x -13)-6(x-13)=0

Take out ( x -13 ) as common ,

\sf\implies ( x -13)(x-6)=0

Equate both factors to 0 ,

\sf\implies \boxed{\pink{\sf x = 13,6}}

<u>Hence</u><u> the</u><u> </u><u>value</u><u> of</u><u> </u><u>x</u><u> is</u><u> </u><u>1</u><u>3</u><u> </u><u>or </u><u>6</u><u> </u><u>.</u>

7 0
3 years ago
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