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anygoal [31]
2 years ago
9

WILL MARK BRAINILIST!!

Mathematics
1 answer:
aleksklad [387]2 years ago
6 0

Answer:

I think the answer is B because i counted all the beads the students had picked out and then put it as the denominato,r and then put the red colored beads as the numerator.

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Based only on the information given in the diagram, which congruence theorems or postulates could be given as reasons why HEL PM
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Please be a little more specific on what you want to ask.
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19. A spherical balloon has a circumference of 19cm. what is the approximate surface area of the balloon to the nearest square c
Tamiku [17]
The main formula of a spherical surface area is SA= 4 x Pi x r²
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SA= 4x 3.14x 3.02² =114.5, the nearest square centimeter is <span>A) 114 cm^2</span>
5 0
3 years ago
Find slope<br><br> A.1/2<br> B.-1/2<br> C.-2<br> D.2
fomenos

Answer:

Option B, -1/2

Step-by-step explanation:

<u>The slope is change in y over change in x.</u>

<u />

<em>Since this line is facing downward, we already know that the slope is negative.</em>

<em />

<u>To find the ratio, find the change in y and divide the change in x.</u>

<em>Change in y = -1</em>

<em>Change in x = 2</em>

<em />

<u>Change in y over change in x:</u>  <em>-1/2</em>

Answer:  Option B, -1/2

6 0
3 years ago
Solve by using Substitution, please help! Show work if you can!
ioda
Hey sorry if I cant show work but here is the point form:
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5 0
3 years ago
Read 2 more answers
For a 4-unit class like Statistics, students should spend average of 12 hours studying for the class. A survey was done on 24 st
Zanzabum

Answer:

a) 68% of the students spend between 10.2 hours and 15.8 hours on Statistics each week.

b) 95% of the students spend between 7.4 hours and 18.6 hours on Statistics each week.

c) 99.7% of the students spend between 4.6 hours and 21.4 hours on Statistics each week.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed(bell-shaped) random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 13 hours

Standard deviation = 2.8 hours.

a) 68% of the students spend between hours and hours on Statistics each week.

Within 1 standard deviation of the mean.

13 - 2.8 = 10.2 hours

13 + 2.8 = 15.8 hours

68% of the students spend between 10.2 hours and 15.8 hours on Statistics each week.

b) 95% of the students spend between hours and hours on Statistics each week.

Within 2 standard deviations of the mean

13 - 2*2.8 = 7.4 hours

13 + 2*2.8 = 18.6 hours

95% of the students spend between 7.4 hours and 18.6 hours on Statistics each week.

c) 99.7% of the students spend between hours and hours on Statistics each week.

Within 3 standard deviations of the mean

13 - 3*2.8 = 4.6 hours

13 + 3*2.8 = 21.4 hours

99.7% of the students spend between 4.6 hours and 21.4 hours on Statistics each week.

8 0
3 years ago
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