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zubka84 [21]
3 years ago
10

Which of the following transports electricity between objects in a circuit?

Chemistry
1 answer:
nirvana33 [79]3 years ago
3 0

Answer:

Wire.

Explanation:

The wire has movable electrons, which moves the charge and the electricity around.

Battery provides the electricity by electrical potential energy, not transport it.

The switch toggles between an open circuit and a closed one, where only the closed one has a full loop of wire to transport electricity.

And the light bulb uses electricity.

Hope this helped!

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An acorn with a mass of .0300 kilograms is hanging from a branch in a tree. It is 2.50 meters from the ground. What is the poten
lorasvet [3.4K]
The answer is the first one. Hope this helps!!!!
6 0
4 years ago
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All the oxides of nitrogen have positive values of G at 298K but only one common oxide of nitrogen has a positive S identify tha
Maurinko [17]

Answer:

The common oxide of nitrogen that has a positive ΔS°f is nitric oxide (NO)

Explanation:

Without reference to thermodynamic data, we have;

1) N₂ (g) + O₂ (g) ⇄ 2 NO (g)

1 unit of N₂ + 1 unit of O₂ (total of 2 units) gives 2 units of NO, (Increase of +0 disorder)

∴ΔS°f = +ve

2) 2NO + O₂ → 2NO₂

2 unit of NO + 1 unit of O₂ (total of 3 units) gives 2 units of NO₂, (Decrease of disorder)

∴ΔS°f = -ve

3) N₂ + 1/2 O₂ → N₂O

1 unit of N₂ + 1/2 unit of O₂ (total of 1+1/2 units) gives 2 units of NO₂, (Decrease of disorder)

∴ΔS°f = -ve

4) 4 NO₂ + O₂ → 2N₂O₅

4 unit of NO₂ + 1 unit of O₂ (total of 5 units) gives 2 units of N₂O₅, (Decrease of disorder)

∴ΔS°f = -ve

5) NO + NO₂ ⇄ N₂O₃

1 unit of NO + 1 unit of NO₂ (total of 2 units) gives 1 unit of N₂O₃, (Decrease of disorder)

∴ΔS°f = -ve

Therefore, the common oxide of nitrogen that has a positive ΔS°f without reference to thermodynamic data is nitric oxide NO.

6 0
3 years ago
H
Irina18 [472]

Answer:

Hehehe :)

Interesting.

Phase 1.

Zinc heated in Air

2Zn + O₂ = 2ZnO

Zinc Oxide is formed.

SOLID A = (ZnO)ZINC OXIDE

Phase 2.

Zinc Oxide is heated with Powdered Magnesium.

magnesium would displace Zinc since its higher in the series.

ZnO + Mg = MgO + Zn

SOLID B + SOLID C = MgO(Magnesium Oxide) + Zn(Zinc metal)

At Phase 3...( 1st Aspect)

Both MgO and Zn can react with Dilute HCl.

Now the products required from the question are a "SOLUTION D" AND "GAS E".

When MgO reacts with Dilute HCl

The products are

MgO + 2HCl = MgCl₂ + H₂O

Now H₂O could be steam(gas) or Water :(

This is a little Uncertain.

But if we use Zn as the one reacting with Dilute HCl

We have

Zn + 2HCl = ZnCl₂ + H₂

Now I'll go with this cos H₂ is simply Hydrogen Gas.

SOLUTION D + GAS E = ZnCl₂(Zinc Chloride) + H₂(Hydrogen Gas)

2nd aspect of Phase 3 ( or denominator)

ELECTROLYSIS OF MOLTEN B

B = MgO

MOLTEN B = MOLTEN MAGNESIUM CHLORIDE.

From Electrolysis of MgO

Mg²⁺ + 2e- = Mg

2O²⁻ = O₂ + 2e⁻

Combining Both Equations.

Mg²⁺ + 2O²⁻ = 2Mg(ₛ) + O₂(g)

Magnesium is a Silvery Metal :)

and Oxygen is a Gas.

Wow!!!

So this automatically makes "SILVERY METAL F" AND "GAS G" TO BE MAGNESIUM AND OXYGEN RESPECTIVELY.

SILVERY METAL F = MAGNESIUM

SILVERY METAL F = MAGNESIUMGAS G = OXYGEN

All the way down to phase 5 now.

Hope you're with me?

Now CuSO₄ is added to Mixture of Mg and O₂. Oxygen would prolly escape into the atmosphere

Leaving Mg to react with CuSO₄

Mg + CuSO₄ = MgSO₄(aq) + Cu(s)

Copper when precipitated from solution sometimes has Brown Pink Color.

MgSO₄ is Solid.

Niceeeee

That's exactly what they need as the answer.

Automatically...

BROWN PINK SOLID H = COPPER(CU)

SOLUTION I = MgSO₄(MAGNESIUM SULPHATE)

Hope this Helps :)

Have a great day.

3 0
3 years ago
10 points
barxatty [35]

Answer:

110k because 2 x 110 =220

7 0
3 years ago
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D. this is because they consume less resources, but produce just as much power. if this is wrong, which i doubt, it is a.
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