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Nana76 [90]
3 years ago
7

What is an example of a base? carbonic acid sodium carbonate sodium hydroxide hydrochloric acid

Chemistry
1 answer:
Zielflug [23.3K]3 years ago
3 0

Answer:

The answer is sodium hydroxide.

Hope this helps.

You might be interested in
Which atoms were needed to form the sodium nitrite?
alex41 [277]

Answer:

Molecular Formula : NaNO2 or NNaO2 and Molecular Weight:

68.995 g/mol

Explanation:

6 0
3 years ago
Hydrogen and Methanol have both been proposed as alternatives to hydrocarbon fuels. Write balanced reactions for the complete co
Arlecino [84]

Answer:

The order of energy released per mass is

CH₃OH (-2.268 × 10⁴ kJ/kg) < C₈H₁₈ (-4.826 × 10⁴ kJ/kg) < H₂ (-2.835 × 10⁵ kJ/kg)

Explanation:

In order to calculate the enthalpy of a reaction (ΔH°r) we can use the following expression.

ΔH°r = ∑np × ΔH°f(p) - ∑nr × ΔH°f(r)

where

ΔH°f(i) are the enthalpies of formation of reactants and products

ni are the moles of reactants and products

<u>Combustion of hydrogen</u>

H₂(g) + 1/2 O₂(g) ⇒ H₂O(l)

ΔH°r = 2 mol × ΔH°f(H₂O) - 1 mol × ΔH°f(H₂) - 1/2 mol × ΔH°f(O₂)

ΔH°r = 2 mol × (-285.8 kJ/mol) - 1 mol × 0 - 1/2 mol × 0

ΔH°r = -571.6 kJ

571.6 kJ are released when 1 mole of H₂ is burned. The amount of heat released per kilogram is:

\frac{-571.6kJ}{1molH_{2}} .\frac{1molH_{2}}{2.016gH_{2}} .\frac{10^{3}gH_{2} }{1kgH_{2}} =-2.835 \times 10^{5} kJ/kgH_{2}

<u>Combustion of methanol</u>

CH₃OH(l) + 3/2 O₂(g) ⇒ CO₂(g) + 2 H₂O(l)

ΔH°r = 1 mol × ΔH°f(CO₂) + 2 mol × ΔH°f(H₂O) - 1 mol × ΔH°f(CH₃OH) - 3/2 mol × ΔH°f(O₂)

ΔH°r = 1 mol × (-393.5 kJ/mol) + 2 mol × (-285.8 kJ/mol) - 1 mol × (-238.4 kJ/mol) - 3/2 mol × 0

ΔH°r = -726.7 kJ

726.7 kJ are released when 1 mole of CH₃OH is burned. The amount of heat released per kilogram is:

\frac{-726.7kJ}{1molCH_{3}OH} .\frac{1molCH_{3}OH}{32.04gCH_{3}OH} .\frac{10^{3}gCH_{3}OH }{1kgCH_{3}OH} =-2.268 \times 10^{4} kJ/kgCH_{3}OH

<u>Combustion of octane</u>

C₈H₁₈(l) + 12.5 O₂(g) ⇒ 8 CO₂(g) + 9 H₂O(l)

ΔH°r = 8 mol × ΔH°f(CO₂) + 9 mol × ΔH°f(H₂O) - 1 mol × ΔH°f(C₈H₁₈) - 12.5 mol × ΔH°f(O₂)

ΔH°r = 8 mol × (-393.5 kJ/mol) + 9 mol × (-285.8 kJ/mol) - 1 mol × (-208.4 kJ/mol) - 12.5 mol × 0

ΔH°r = -5511.8 kJ

5511.8 kJ are released when 1 mole of C₈H₁₈ is burned. The amount of heat released per kilogram is:

\frac{-5511.8kJ}{1molC_{8}H_{18}} .\frac{1molC_{8}H_{18}}{114.2gC_{8}H_{18}} .\frac{10^{3}gC_{8}H_{18} }{1kgC_{8}H_{18}} =-4.826 \times 10^{4} kJ/kgC_{8}H_{18}

5 0
3 years ago
What element has the same amount of valence electrons as neon?<br> -KDM
Darya [45]

Answer:

Sulfur has the same amount, like all the other elements in group 16, has six valence electrons.

Explanation:

3 0
2 years ago
Read 2 more answers
Changes of state are a result of a change in the______of the matter.
jasenka [17]

Answer: -

Kinetic energy.

Explanation: -

Solids have the least kinetic energy and the highest intermolecular force of attraction among the three states of matter.

When heat energy is supplied to the solid, the kinetic energy of the solid particles increases. At some point, the kinetic energy becomes comparable to the intermolecular force of attraction. At that point solids change into liquids.

When further heat energy is given, at certain point the kinetic energy becomes far greater than the intermolecular forces of attraction. At that point it becomes gas.

4 0
3 years ago
Hydrogen bonds can be found between molecules of which of the following
Lilit [14]

Answer:

The presence of hydrogen bonding between molecules of a substance indicates that the molecules are polar. This means the molecules will be soluble in a polar solvent such as water. Some examples of polar molecules which can hydrogen bond are ammonia ( NH3 ) and methanol ( CH3OH ).

I think the answer should be C

4 0
3 years ago
Read 2 more answers
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