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3 years ago

What is an example of a base? carbonic acid sodium carbonate sodium hydroxide hydrochloric acid

Chemistry

1 answer:

Zielflug [23.3K]3 years ago

3 0

Answer:

The answer is sodium hydroxide.

Hope this helps.

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What is the method of harvesting trees where mature trees are left intact that

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Hey day is the method of harvesting tress.

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2 years ago

Millikan measured the quantity of charge carried

Cloud [144]

Answer:

m = E × Q

And Q = I × t

m = E × I × t

Where m = mass in grams

Q = quantity of electricity in coulomb

I = current in ampere

t = time in seconds

E = electrochemical equivalent of the substance

Explanation:

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3 years ago

A chemist dissolves 484 .mg of pure perchloric acid in enough water to make up 240.mL of solution. Calculate the pH of the solut

sdas [7]

Answer:

1.70

Explanation:

The molar mass of perchloric acid is 100.46 g/mol. The moles corresponding to 484 mg (0.484 g) are:

0.484 g × (1 mol/100.46 g) = 4.82 × 10⁻³ mol

4.82 × 10⁻³ moles are dissolved in 240 mL (0.240 L) of solution. The molar concentration of perchloric acid is:

4.82 × 10⁻³ mol/0.240 L = 0.0201 M

Perchloric acid is a strong monoprotic acid, that is, it dissociates completely, so [H⁺] = 0.0201 M.

The pH is:

pH = -log [H⁺] = -log 0.0201 = 1.70

8 0

3 years ago

A 20.0 g sample of copper at 25.0 °c absorbs 475 j. What is the final temperature of the copper? (specific heat capacity of copp

maks197457 [2]

Given data:

Mass of copper (m) = 20.0 g

Initial temperature of Copper (T1)= 25 C

Final temperature = T2

Heat absorbed by copper (Q) = 475 J

Specific heat of Copper (c) = 0.385 J/g C

Formula:

Q = mcΔT

= mc(T2-T1)

475 = 20*0.385*(T2-25)

62.08 = T2-25

T2 = 87.08 = 87.1 C

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3 years ago

What is the bond order of c2−?express the bond order numerically?

diamong [38]

MO Diagram of C₂⁻ is shown below,

Bond order is calculated as,

Bond Order = [# of e⁻s in BMO]-[#of e⁻s in ABMO] / 2
Where,

BMO = Bonding Molecular Orbital

ABMO = Anti-Bonding Molecular Orbital

Putting values,

Bond Order  =  [9]-[4] / 2

Bond Order  =  5 / 2

Bond Order  =  2.5

6 0

3 years ago

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