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3 years ago

How do you Factor this problem 24x^3+4x^2-4x

Mathematics

2 answers:

Leya [2.2K]3 years ago

5 0

Answer is given above

adoni [48]3 years ago

4 0

Factor out 4x first

4x(6x² + x - 1)

factor the rest as normal, knowing that what adds to give the middle term multiplies to give the last term.

4x(2x + 1)(3x - 1)

You might be interested in

12c + 12 (3/4c) + 12 (1/2c) shows the total cost for buying 3 phones that each cost c dollars per month for 12 months.

alisha [4.7K]

Answer:

c(12 + 9 + 6)

12(2.25c)

Step-by-step explanation:

12c + 12 (3/4c) + 12 (1/2c)

12(1c) + 12(3/4c) + 12 (1/2c)

12(c + 3/4c + 1/2c)

12(2 1/4c)

12(2.25c)

12c + 12 (3/4c) + 12 (1/2c)

12c + 9c + 6c

c(12 + 9 + 6)

6 0

3 years ago

Marcia has $84 less than three times as much as sue. together they have $132. how much money does marcia have?

Brut [27]

Let x = sue
and then let 3x-84 = marcia
therefore
(x)+(3x-84)=132
4x-84=132
4x=216
x=54

however just solving for x doesnt completely solve. it only shows sues money because x = sue
for marcia
3x-84
3(54)-84
162-84
78

therefore Marcia has 78$.

5 0

3 years ago

Plz help I need bt tonight

JulijaS [17]

The answer is 25%.

First: work out the difference between the two numbers you are comparing.

Decrease = Original Number - New Number

35-28=7

Then: divide the decrease by the original number and multiply the answer by 100. % Decrease = Decrease ÷ Original Number × 100

7÷

28=.25

.25*100=25

<h2>Answer is 25%.</h2>

7 0

3 years ago

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of te triangle is 16m to the power of 2, what are the base

Olenka [21]

Answer:

The base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

Step-by-step explanation:

Given:

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of the triangle is 16m to the power of 2.

Now, to find the base and height of the triangle.

The base of triangle = $x\times\frac{1}{2} =\frac{x}{2} \ m.$

The height of triangle = $x\times \frac{3}{4} =\frac{3x}{4}\ m.$

The area of triangle = $16\ m^2.$

Now, we put the formula of area to solve:

$Area=\frac{1}{2} \times base\times height$

$16=\frac{1}{2} \times \frac{x}{2} \times \frac{3x}{4}$

$16=\frac{3x^2}{16}$

Multiplying both sides by 16 we get:

$256=3x^2$

Dividing both sides by 3 we get:

$\frac{256}{3} =x^2$

Using square root on both sides we get:

$\frac{16}{\sqrt{3}}=x$

$x=\frac{16}{\sqrt{3}}$

Now, by substituting the value of $x$ to get the base and height:

$Base=\frac{x}{2}\\\\Base=\frac{\frac{16}{\sqrt{3}}}{2} \\\\Base=\frac{8}{\sqrt{3}} \ m.$

So, the base of triangle = $\frac{8}{\sqrt{3}} \ m.$

$Height=x\times\frac{3}{4} \\\\Height=\frac{16}{\sqrt{3}}\times \frac{3}{4} \\\\Height=\frac{12}{\sqrt{3}} \ m.$

Thus, the height of triangle = $\frac{12}{\sqrt{3}} \ m.$

Therefore, the base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

7 0

4 years ago

I need help please. Thanks

Agata [3.3K]

Given:

m∠APD = (7x + 1)°

m∠DPC = 90°

m∠CPB = (9x - 7)°

To find:

The measure of arc ACD.

Solution:

Sum of the adjacent angles in a straight line = 180°

m∠APD + m∠DPC + m∠CPB = 180°

7x° + 1° + 90° + 9x° - 7° = 180°

16x° + 84° = 180°

Subtract 84° from both sides.

16x° + 84° - 84° = 180° - 84°

16x° = 96°

Divide by 16° on both sides.

x = 6

m∠APB = 180°

m∠BPD = (9x - 7)° + 90°

= (9(6) - 7)° + 90°

= 47° + 90°

m∠BPD = 137°

m∠APD = m∠APB + m∠BPD

= 180° + 137°

= 317°

The measure of the central angle is congruent to the measure of the intercepted arc.

m(ar ACD) = m∠APD

m(ar ACD) = 317°

The arc measure of ACD is 317°.

8 0

3 years ago