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Levart [38]
4 years ago
13

classify each angle pair using all the names that apply using the diagram on the left , answering 1 2 3 4 and 5 , explain why.(

I'm not sure if the answers on the paper are correct ).​

Mathematics
1 answer:
vredina [299]4 years ago
6 0

Answer:

  see the attachment

Step-by-step explanation:

1.  Two angles that sum to 90° are <em>complementary</em>, whether they are adjacent or not. Angles LMN and NMP are also <em>adjacent</em>.

2.  Vertical angles created by two distinct lines are <em>never adjacent</em>. The sides of the angles are created by the same lines, and the angles share a vertex, but there is no ray that is a side common to both angles.

3.  Angle GMK is supplementary to angle JMG.

4.  Vertical angles are congruent. See question 2.

5.  See question 1.

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Given the expression below, identify its factors.<br><br> 3a + 4b– 7c - 12
Mkey [24]

Answer:

i dont think you can solve this because  

The expression is not factorable with rational numbers.

there are no like terms

4 0
3 years ago
Elenas anut bought her a 150$ saving bond when she was born. When elena is 18 years old, the bond will have earned a 106% in int
SpyIntel [72]

Answer:

The Amount after 18 years is $66,942,391.5

Step-by-step explanation:

Given as :

The principal invested in saving bond = p = $150

The Time period for the bond = t = 18 years

The rate of interest applied on bond = 106%

Let The Amount after 18 years = $A

<u>Now, From compound interest</u>

Amount = Principal × (1+\dfrac{\textrm rate}{100})^{\textrm time}

Or, A = p × (1+\dfrac{\textrm r}{100})^{\textrm t}

Or, A = $150 × (1+\dfrac{\textrm 106}{100})^{\textrm 18}

Or, A = $150 × (2.06)^{\textrm 18}

Or, A = $150 × 446,282.61

∴ A = $66,942,391.5

So,The Amount after 18 years = A = $66,942,391.5

Hence,The Amount after 18 years is $66,942,391.5 Answer

7 0
3 years ago
Can someone helpppp meee?!!!:))
Slav-nsk [51]

Answer:

3(x+6)=3x+18 = infinite

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5(x-3)=15+5x = no solution

5 0
3 years ago
Which length is equivalent to 357 centimeters?<br><br> 0.357 m<br> 3.57 m <br> 35.7 m<br> 3570 m
babymother [125]
3.57 m
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7 0
3 years ago
Need help on these !! 13 and 14! Please!!
katen-ka-za [31]

Question # 13

Answer:

The required equation for the given function is <em>y = 4sin(x/2+2π/3) -2 , as shown attached graph diagram.</em>

<em>Step-by-step explanation: </em>

As the general sine function is given by

y=asin(bx+c)+d.......[A]

  • amplitude = a
  • period = 2π ÷ b
  • Phase shift = -c ÷ b
  • Vertical shift = d

As in the question,  

  • amplitude = a = 4
  • period = 4π
  • phase shift = -4π/3
  • Vertical shift = d = -2

As  

period = 2π ÷ b  

b = 2π/period

b = 2π/4π ∵ period = 4π

b = 1/2  

Also

Phase shift = -c/b

-4π/3 = -c/b ∵ phase shift = -4π/3

4π/3 = c/b  

c = b × 4π/3  

c = 1/2 × 4π/3  

c = 4π/6  

c = 2π/3

So, putting Amplitude ⇒ a = 4, Vertical shift ⇒ d = -2, b = 1/2 ,  

and c = 2π/3 in Equation [A] would bring us the required equation for the given function.

y=asin(bx+c)+d

y = 4sin(x/2+2π/3)+(-2)

y = 4sin(x/2+2π/3) -2            

<em>Note: The graph is also shown in attached diagram.</em>

                                             Question # 14

<em>Answer:</em>

The required equation for the given function is y = cot(x+π/3)+2, as shown in attached graph diagram.

<em>Step-by-step explanation: </em>

As the general cotangent function is given by

y=acot(bx+c)+d.......[A]

  • amplitude = a
  • period = π ÷ b
  • Phase shift = -c ÷ b
  • Vertical shift = d

As in the question,  

  • period = π
  • phase shift = -π/3
  • Vertical shift = d = 2

As  

period = π ÷ b  

b = π/period

b = π/π ∵ period = 4π

b = 1  

Also

Phase shift = -c/b

-π/3 = -c/b ∵ phase shift = -π/3

π/3 = c/b  

c = b × π/3  

c = 1 × π/3  

c = π/3

So, putting vertical shift ⇒ d = 2, b = 1 and   c = π/3 in Equation [A] would bring us the required equation for the given function.

y=acot(bx+c)+d

y = cot(x+π/3)+2

<em>Note: The graph is also shown in attached diagram.</em>

Keywords: amplitude, period , phase shift , vertical shift

Learn more about trigonometric functions of equations from brainly.com/question/2643311

#learnwithBrainly

7 0
4 years ago
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