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weqwewe [10]
3 years ago
10

What is the equation of a circle centered at the origin with radius 20.. i cant find the answer and i even tried?

Mathematics
2 answers:
pogonyaev3 years ago
7 0

Answer:

Required equation of circle is x² + y² = 400

Step-by-step explanation:

We are given center of the circle i origin and radius = 20 units.

We have to find the equation of the circle.

We know that coordinates of the origin is ( 0 , 0 )

To write the equation of circle we use standard equation of circle,

Standard equation of circle is given as below,

( x - h )² + ( y - k )² = r²

here, ( h , k ) is coordinate of the center of the circle. and r is radius of the circle.

Using given information and standard equation of circle, we have

( x - 0 )² + ( y - 0 )² = 20²

x² + y² = 400

Therefore, Required equation of circle is x² + y² = 400

KIM [24]3 years ago
4 0
General equation of a circle with centre (h, k) is given by:

(x - h)^{2} + (y - k)^{2} = r^{2}

Now, the origin is the centre and radius is 20, so substituting these points in yields:
x^{2} + y^{2} = 20^{2}
x^{2} + y^{2} = 400
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What is the gcf of 3/7 and 4/9?
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Answer:

  1/63

Step-by-step explanation:

There are a couple of ways to do this.

<h3>1) </h3>

Look for the GCF of the numerators when a common denominator is used.

  GCF(3/7, 4/9) = GCF(27/63, 28/63) = (1/63)·GCF(27, 28)

  GCF(3/7, 4/9) = 1/63

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<h3>2) </h3>

Use Euclid's algorithm. If the remainder from division of the larger by the smaller is zero, then the smaller is the GCF; otherwise, the remainder replaces the larger, and the algorithm repeats.

  (4/9)/(3/7) = 1 remainder 1/63*

  (3/7)/(1/63) = 27 remainder 0

The GCF is 1/63.

__

* The quotient is 28/27 = 1 +1/27 = 1 +(1/27)(3/7)/(3/7) = 1 +(1/63)/(3/7) or 1 with a remainder of 1/63.

_____

<em>Additional comment</em>

3/7 = (1/63) × 27

4/9 = (1/63) × 28

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