All categories

3 years ago

Helppppppp

Mathematics

1 answer:

puteri [66]3 years ago

7 0

Answer:

15 days

Step-by-step explanation:

Since he used both of the weights today, he will only do both on the day they come together.

weights: 3 days, 6 days, 9 days, 12 days, 15 days

machine: 5 days, 10 days, 15 days

Because the numbers both were the same on 15 days, then that is when he will do both of them

You might be interested in

Which shape is always a rhombus?

GREYUIT [131]

Answer:

B- A square because it has 4 sides that are the same length.

Explain:

I misread earlier, but a rhombus is defined as a quadrilateral with four equal-legnth sides and opposite sides parallel to each other. All squares have all of these properties.

3 0

3 years ago

Initial value problems dy/dx+2y=3. Y(0)=1

Pavel [41]

The initial value equation is $y = \frac 12(3 - e^{-2x})$

<h3>How to solve the initial value?</h3>

The equation is given as:

$\frac{dy}{dx} +2y = 3$

Where

Y(0) = 1

Subtract 2y from both sides in the equation

$\frac{dy}{dx} = -2y + 3$

Rewrite as:

$\frac{dy}{-2y + 3} = dx$

Integrate both sides of the equation

$-\frac 12\ln|-2y + 3| = x + C_o$

Multiply through by -2

$\ln|-2y + 3| = -2x + C_1$

Take the exponent of both sides

$-2y + 3 = Ce^{-2x$

Next, we solve for C under the initial condition Y(0) = 1.

This gives

$-2(1) + 3 = Ce^{-2 * 0$

Evaluate

-2 + 3 = C

Solve for C

C = 1

Substitute C = 1 in $-2y + 3 = Ce^{-2x$

$-2y + 3 = e^{-2x$

Next, we solve for y

$y = \frac 12(3 - e^{-2x})$

Hence, the initial value equation is $y = \frac 12(3 - e^{-2x})$

Read more about initial value at:

brainly.com/question/16945606

#SPJ1

3 0

2 years ago

Help asap please

larisa86 [58]

Answer- D.
The +1850 is the y intercept

8 0

3 years ago

Read 2 more answers

Hello, can someone help me with this problem?

exis [7]

Answer:

Area of Rectangle A

$Area = 4x^2$

Area of Rectangle B

$Area = 2x^2$

Fraction

$Fraction =\frac{2}{3}$

Step-by-step explanation:

From the attached, we understand that:

The dimension of rectangle A is 2x by 2x

The dimension of rectangle B is x by 2x

Area of rectangle is calculated as thus;

$Area = Length * Breadth$

Area of Rectangle A

$Area = 2x * 2x$

$Area = 4x^2$

Area of Rectangle B

$Area = x * 2x$

$Area = 2x^2$

Area of Big Rectangle

The largest rectangle is formed by merging the two rectangles together;

The dimension are 3x by 2x

The Area is as follows

$Area = 2x * 3x$

$Area = 6x^2$

The fraction of rectangle A in relation to the largest rectangle is calculated by dividing area of rectangle A by area of the largest rectangle;

$Fraction = \frac{Rectangle\ A}{Biggest}$

$Fraction =\frac{4x^2}{6x^2}$

Simplify

$Fraction =\frac{2x^2 * 2}{2x^2 * 3}$

$Fraction =\frac{2}{3}$

7 0

3 years ago

I got letter C as my answer, is that correct?

lisov135 [29]

Yes it is C if you do the math and simplify it that is what you’ll get

4 0

3 years ago