Answer:
(a). The electric potential at 1.650 cm is
.
(b). The electric potential at 2.81 cm is
.
Explanation:
Given that,
Radius of sphere R=2.81 cm
Charge = +2.35 fC
Potential at center of sphere

(a). We need to calculate the potential at a distance r = 1.60 cm
Using formula of potential difference






The electric potential at 1.650 cm is
.
(b). We need to calculate the potential at a distance r = R
Using formula of potential difference



The electric potential at 2.81 cm is
.
Hence, This is the required solution.
Answer:
50m; 0m/s.
Explanation:
Given the following data;
Initial velocity = 20m/s
Acceleration, a = - 4m/s²
Time, t = 5secs
To find the displacement, we would use the second equation of motion;

Substituting into the equation, we have;



S = 50m
Next, to find the final velocity, we would use the third equation of motion;
Where;
- V represents the final velocity measured in meter per seconds.
- U represents the initial velocity measured in meter per seconds.
- a represents acceleration measured in meters per seconds square.
<em>Substituting into the equation, we have;</em>
V = 0m/s
<em>Therefore, the displacement of the bus is 50m and its final velocity is 0m/s.</em>
Answer:
X: period
Y: tangential speed
Explanation:
100% on quiz your welcome(:
I think the answer may be the letter B
6,5 6,4 6,3 6,2 6
if you know,1