Refer to the diagram shown below.
The angle θ = 15° relative to the direction of motion.
Therefore the force acting in the direction of motion is
(12 N) cos(15°) = 11.59 N
By definition,
Work = Force x Distance.
Therefore work done in moving the sled by 25 m is
Work = (11.59 N)*(25 m) = 289.8 J
Answer: 289.8 J
Answer:
Bottle opener works on a fulcrum.
Explanation:
A bottle opener is a second-class lever because the pivot point is at one end of the opener and the load is in the middle.
Answer:
I believe it would be B, Mars.
Hope this helps!
Answer:
E = 1/2 M V^2 + 1/2 I ω^2 = 1/2 M V^2 + 1/2 I V^2 / R^2
E = 1/2 M V^2 (1 + I / (M R^2))
For a cylinder I = M R^2
For a sphere I = 2/3 M R^2
E(cylinder) = 1 + 1 = 2 omitting the 1/2 M V^2
E(sphere) = 1 + 2/3 = 1.67
E(cylinder) / E(sphere) = 2 / 1.67 = 1.2
The cylinder initially has 1.20 the energy of the sphere
The PE attained is proportional to the initial KE
H(sphere) = 2.87 / 1/2 = 2.40 m since it has less initial KE