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a 20N mass is supported by two ropes. what is the tension in each rope? how woould i work this problem if i know the two angles

TiliK225 [7]

Before we could discuss this in any specific detail, I think we would have to
know the angles. A generic discussion without actual numbers for the angles
would be just plain too confusing.

The general approach is that the vertical components of both tensions
add up to 20N, and the horizontal components are equal but in opposite
directions. That's the only way that the mass is hanging motionless.

You have to find the horizontal and vertical components of the tensions
by using the angles and maybe the lengths of the ropes.

5 0

3 years ago

What is the acceleration of this object? The object's mass is 60 kg.

Licemer1 [7]

First determine the net force. Let's say the downwards force is negative and the upwards force is positive.
Since the forces act in opposite directions, the net force would be:
400N - 600N = -200N

Since I said negative is downwards, this translates to the net force being 200N downwards.

Force = mass*acceleration
200N = 60kg * acceleration
acceleration = 3.33 m/s^2

5 0

3 years ago

Read 2 more answers

A pitcher delivers a fast ball with a velocity of 43 m/s to the south. the batter hits the ball and gives it a velocity of 51 m/

hoa [83]

Assuming north as positive direction, the initial and final velocities of the ball are:
$v_i=-43 m/s$ (with negative sign since it is due south)
$v_f=+51 m/s$
the time taken is $t=1.0 ms=0.001 s$ , so the average acceleration of the ball is given by
$a= \frac{v_f-v_i}{t}= \frac{51 m/s-(-43 m/s)}{0.001 s}=9.4 \cdot 10^4 m/s^2$
And the positive sign tells us the direction of the acceleration is north.

4 0

3 years ago

A charge of Q is fixed in space. A second charge of q was first placed at a distance r1 away from Q. Then it was moved along a s

topjm [15]

Answer:

$\Delta U = \frac{Qq}{4\pi\epsilon_0}(\frac{1}{r_2^2}-\frac{1}{r_1^2})$