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2 years ago

For typical rubber-on-concrete friction, what is the shortest time in which a car could accelerate from 0 to 50 mph

Physics

1 answer:

SVEN [57.7K]2 years ago

6 0

Answer:

2.5sec

Explanation:

for the typical rubber on concrete it will take 2.5seconds which is the shortest time.

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Manipulate the equation "v=d/t" to find the answers to these problems using

OLEGan [10]

Yo no me voy a ir a la cama a

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2 years ago

On a clear day at a certain location, a 119-V/m vertical electric field exists near the Earth's surface. At the same place, the

IrinaVladis [17]

Answer:

(a) 62.69 nJ/m^3

(b) 1015.22 μJ/m^3

Explanation:

Electric field, E = 119 V/m

Magnetic field, B = 5.050 x 10^-5 T

(a) Energy density of electric field = $\frac{1}{2}\varepsilon _{0}E^{2}$

$=\frac{1}{2}\times 8.854\times 10^{-12}\times 119\times 119$

= 6.269 x 10^-8 J/m^3 = 62.69 nJ/m^3

(b) energy density of magnetic field = $\frac{B^{2}}{2\mu _{0}}$

$=\frac{\left ( 5.05\times 10^{-5} \right )^{2}}{2\times 4\times 3.14\times 10^{-7}}$

= 1.01522 x 10^-3 J/m^3 = 1015.22 μJ/m^3

8 0

3 years ago

Ballistic data obtained on a firing range show that aerodynamic drag reduces the speed of a .44 magnum revolver bullet from 250

m_a_m_a [10]

Answer:

0.363999909622

Explanation:

F = Force

m = Mass = 15.6 g

C = Drag coefficient

ρ = Density of air = 1.21 kg/m³

A = Surface area = $\dfrac{\pi}{4}d^2$

v = Terminal velocity = $v=210\ m/s$

s = Displacement = 150 m

$a=\dfrac{v^2-u^2}{2s}$

Force is given by

F = ma

$F=\dfrac{1}{2}\rho CAv^2\\\Rightarrow ma=\dfrac{1}{2}\rho CAv^2\\\Rightarrow m\dfrac{v^2-u^2}{2s}=\dfrac{1}{2}\rho CAv^2\\\Rightarrow C=2\times m\dfrac{v^2-u^2}{2s}\times\dfrac{1}{\rho Av^2}\\\Rightarrow C=2\times15.6\times 10^{-3}\dfrac{210^2-250^2}{2\times 150}\times\dfrac{1}{1.21\times\dfrac{\pi}{4}\times (11.2\times 10^{-3})^2(210)^2}\\\Rightarrow C=-0.363999909622$

The drag coefficient is 0.363999909622 (ignoring negative sign)

4 0

2 years ago

Viewed from a distance, how would a flashing red light appear as it fell into a black hole?.

Pachacha [2.7K]

Explanation:

Light rays that pass close to the black hole get caught and cannot escape. so what ends up happening to the light is that it starts bending due to the strong gravitational force of the black hole.

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1 year ago

Suppose you altered your existing ramp so that the marbles had twice their initial velocity right before leaving the ramp. How w

s344n2d4d5 [400]

Answer:

#see details below.

Explanation:

-The net distance travelled would double because they had double the horizontal speed.

-The marbels would consequently spend about the same time in the air since vertical motion is not affected.

8 0

2 years ago