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Marrrta [24]
3 years ago
13

15. Which number is equivalent to 0.000001: 10^6 or 10^-6? Explain how you know. Plz help me

Mathematics
1 answer:
atroni [7]3 years ago
3 0
Dannng I thought I seen this one before
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Use substitution to solve the following system of equations. What is the value of y? {3x+2y=12{5x−y=7 A) y = -3B) y = 3C) y = -2
Vlad [161]

<em>Answer</em>

B) y = 3

<em>Step-by-step explanation</em>

Given the system of equations:

\begin{gathered} 3x+2y=12\text{ \lparen eq. 1\rparen} \\ 5x-y=7\text{ \lparen eq. 2\rparen} \end{gathered}

Isolating x from equation 1:

\begin{gathered} 3x+2y-2y=12-2y \\ 3x=12-2y \\ \frac{3x}{3}=\frac{12-2y}{3} \\ x=\frac{12}{3}-\frac{2}{3}y \\ x=4-\frac{2}{3}y\text{ \lparen eq. 3\rparen} \end{gathered}

Substituting equation 3 into equation 2 and solving for y:

\begin{gathered} 5(4-\frac{2}{3}y)-y=7 \\ 5\cdot4-5\cdot\frac{2}{3}y-y=7 \\ 20-\frac{10}{3}y-y=7 \\ 20-\frac{13}{3}y=7 \\ 20-\frac{13}{3}y-20=7-20 \\ -\frac{13}{3}y=-13 \\ (-\frac{3}{13})\cdot-\frac{13}{3}y=(-\frac{3}{13})\cdot-13 \\ y=3 \end{gathered}

6 0
11 months ago
50(1.05)t &lt; 100 how much growth or decay
makvit [3.9K]
50(1.05)t \ \textless \  100

3 0
3 years ago
Which of the following graphs are identical
Lady bird [3.3K]

Answer:

The domain is x ≥ -7

Step-by-step explanation:

The domain asks what values can x take

We know that the sqrt(x+7) must be ≥ 0

That means the smallest value it can be is zero

x+7 ≥ 0

x ≥ -7

The domain is x ≥ -7

5 0
3 years ago
Can someone please answer this and explain it?
professor190 [17]

Answer:

Velocity = displacement / time

Distance = 3t^2 +2t +6 to find distance you need to plug in time = 2 sec

Distance = 3(2)^2 +2(2) +6

Distance = 3(4) +4 + 6

Distance = 12 + 4 +6

Distance = 22 meters

In this problem the displacement is the distance.

so

Velocity = 22 meters / 2 second

Velocity = 11 meters/second

Does this help?

Step-by-step explanation:

4 0
3 years ago
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Travka [436]

Answer:

Are we human, or are we dancer

Step-by-step explanation: this is an answer your teacher would love trust me ;)

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