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3 years ago

Which is the best description for this histogram?

Mathematics

2 answers:

lbvjy [14]3 years ago

6 0

Answer:

a. it is symmetrical

have a great day!

swat323 years ago

4 0

Answer:

A. It is symmetrical.

Step-by-step explanation:

You might be interested in

Round 0.971 to the nearest tenth

Flura [38]

Answer:

1.0

Step-by-step explanation:

You are rounding to the nearest tenth, so you should have only 2 places remaining (0.0). So, you look to the 7 to change the 9. 7 is bigger than 5, so you round 9 up. Since 9 plus 1 equals 10, the final answer is 1.0.

Hope this helps! :)

5 0

4 years ago

Read 2 more answers

Which method will NOT get you to the point (4,3.5)?

lesantik [10]

Answer:

A. Starting at the origin, go 3.5 spaces to the right and then 4 spaces up.

Step-by-step explanation:

if you were to plot this then the point would be (3.5,4) instead of (4,3.5)

3 0

3 years ago

4.) Which best describes the relationship between < AFB and < AFD?

MAVERICK [17]

Answer:

C. Supplementary angles

Step-by-step explanation:

Given

<AFB = 72

Required

Relationship of <AFB and <AFD

<AFB and <AFD are on a straight line and angle on a straight line is 180

From the presentation of both angles,

<AFB + <AFD = 180

Substitute 72 for <AFB

72 + <AFD = 180

Make <AFB the subject of formula

<AFD = 180 - 72

<AFD = 108

Since both <AFB and <AFD sums to 180, then they are supplementary angles.

Hence, the relationship between both angles is supplementary angles

5 0

4 years ago

Find the unit rate for miles per hour. Round to the nearest hundredth if necessary. A cyclist rides 65 miles in 3 hours.

Natasha2012 [34]

22 (rounded to the nearest one)

4 0

3 years ago

Which equation has the solutions x=1+or-square root of 5?

stiv31 [10]

We will proceed to solve each case to determine the solution of the problem.

case a) $x^{2}+2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=-4+1$

$x^{2}+2x+1=-3$

Rewrite as perfect squares

$(x+1)^{2}=-3$

$(x+1)=(+/-)\sqrt{-3}\\(x+1)=(+/-)\sqrt{3}i\\x=-1(+/-)\sqrt{3}i$

therefore

case a) is not the solution of the problem

case b) $x^{2}-2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=-4+1$

$x^{2}-2x+1=-3$

Rewrite as perfect squares

$(x-1)^{2}=-3$

$(x-1)=(+/-)\sqrt{-3}\\(x-1)=(+/-)\sqrt{3}i\\x=1(+/-)\sqrt{3}i$

therefore

case b) is not the solution of the problem

case c) $x^{2}+2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=4+1$

$x^{2}+2x+1=5$

Rewrite as perfect squares

$(x+1)^{2}=5$

$(x+1)=(+/-)\sqrt{5}\\x=-1(+/-)\sqrt{5}$

therefore

case c) is not the solution of the problem

case d) $x^{2}-2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=4+1$

$x^{2}-2x+1=5$

Rewrite as perfect squares

$(x-1)^{2}=5$

$(x-1)=(+/-)\sqrt{5}\\x=1(+/-)\sqrt{5}$

therefore

case d) is the solution of the problem

therefore

the answer is

$x^{2}-2x-4=0$

5 0

3 years ago

Read 2 more answers