Question

A room has an area of 432 ft2. One dimension is 6 ft more than the other. Find the dimensions of the room.

Answer 1

Answer:

W=18ft

L=24ft

Step-by-step explanation:

Step one:

given data

area= 425ft^2

let the width W be =x

and the length L be =x+6

Required

Length and width

solution

Area= lenth*width

432=x*(x+6)

432=x^2+6x

x^2+6x-432=0

The roots of the quadratic equation is

x=-24-----can not be negative

x=18----correct

The dimension is

the width W =x=18ft

The length= x+6=18+6=24ft

check area= 18*24=432ft^2