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babunello [35]
2 years ago
14

How do I do this problem?

Mathematics
2 answers:
klemol [59]2 years ago
7 0

Step-by-step explanation:

here is the answer to your question

alina1380 [7]2 years ago
6 0

Answer:

Step-by-step explanation:

I would start from the beginning and find the slope myself, just so I know what's going on (as opposed to being dropped in the middle of the problem). The slope formula is:

m=\frac{y_2-y_1}{x_2-x_1} and for us:

m=\frac{5-3}{4-3}=2 so the slope is indeed 2. Now we need to write the equation in slope-intercept form. I find it easier to first write the equation in point-slope form and then solve it for y. Point-slope form is

y-y_1=m(x-x_1) where m is the slope (2) and x1 and y 1 are from one of the coordinates (whichever one you want; as long as you do the math correctly, you will NOT get an incorrect answer. In other words, you can't pick the "wrong" point to use to write the equation.) I'm going to use (3, 3):

y - 3 = 2(x - 3) and

y - 3 = 2x - 6 and

y = 2x - 6 + 3 so

y = 2x - 3 and that's your equation. Of course, you will enter a (-3) in that box with the ? in it.

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3x2 + 7x for x =2<br> Solve
kaheart [24]

Answer:

26

Step-by-step explanation:

3x^2 + 7x

when x = 2,

=> 3(2)^2 + 7(2)

=> 3(4) + 14

=> 12 + 14

=> 26

8 0
2 years ago
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iVinArrow [24]

Answer:

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Step-by-step explanation:

width×Length

9×9+13

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2 years ago
What is an equation of the line that passes through the points (0, 2) and ( 5, 4)?
creativ13 [48]

Answer: y = 2/5 x + 2

Step-by-step explanation:

why not do this one too yk

slope = y2 - y1 / x2 - x1

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slope = 2/5

ill use (5,4) for the y=mx+b initial equation

y = mx+b

4 = (2/5)(5) +b

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7 0
2 years ago
The amount of money in dollars in a na account after t years is given
iren [92.7K]
What are the number or what is the equation.What amount of dollars
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3 years ago
Not sure how to do #69, it's a calc 1 question
Gnoma [55]
Let A( t , f( t ) ) be the point(s) at which the graph of the function has a horizontal tangent => f ' ( t ) = 0.

But, f ' ( x ) = [ ( x^2 ) ' * ( x - 1 ) - ( x^2 ) * ( x - 1 )' ] / ( x - 1 )^2 =>
f ' ( x ) = [ 2x( x - 1 ) - ( x^2 ) * 1 ] / ( x - 1 )^2 => f ' ( x ) = ( x^2 - 2x ) / ( x - 1 )^2;

f ' ( t ) = 0 <=> t^2 - 2t = 0 <=> t * ( t - 2 ) = 0 <=> t = 0 or t = 2 => f ( 0 ) = 0; f ( 2 ) = 4 => A 1 ( 0 , 0 ) and A 2 ( 2 , 4 ).
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2 years ago
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