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Nat2105 [25]
3 years ago
14

What makes a bivalve a bivalve​

Chemistry
1 answer:
Brums [2.3K]3 years ago
3 0

Answer:

Bivalve, (class Bivalvia), any of more than 15,000 species of clams, oysters, mussels, scallops, and other members of the phylum Mollusca characterized by a shell that is divided from front to back into left and right valves. ...

Explanation:

hope it helps.^^

#carryonlearning

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Pls help...
rjkz [21]

Answer: c

Explanation:

4 0
3 years ago
Read 2 more answers
Can someone please help with this I need the answers for the three boxes
denis23 [38]

Answer:

Type: M

Name: Dixytrogen Pentasulfide

Molar Mass:

X*2 = Number * 2 = Number

S*5=32.066*5=160.33

Number + 160.33 = Molar Mass (g/mol).

(The mass for Xytrogen is not present).

Explanation:

Assuming Xytrogen is a non-metal and bonding it with sulfur, another non-metal would make it covalent or molecular.  

The name is from the amount of Xs (being two [Di]) and the amount of Ss (being five [Penta]).

The molar mass is explained above.  You need to multiply the mass of each element by the number of elements present in the compound.  The mass for Xytrogen is not present (as it is a made up element) so I left instructions how to do it once given the mass instruction.

Hope this helps.

6 0
3 years ago
What does it mean for a chemical equation to be balanced?
Troyanec [42]

it is c because i did this with my teacher and we are doing about chemical atoms

7 0
3 years ago
Give the major product formed when phenol is heated with concentrated H2SO4 and SO3. (There is more than one correct answer, but
iris [78.8K]

Answer:

See image attached and explanation

Explanation:

The reaction of phenol with SO3/H2SO4 is an electrophilic reaction. The electrophile attacks portions of high electron density in the substrate phenol.

The -OH group activates phenol towards electrophilic substitution at the ortho and para positions, hence the product(s) formed in this reaction(only one product is shown here as required by the question).

The sulphonation of phenol using concentrated sulfuric acid at lower temperature yields majorly the ortho product whereas at higher temperature the para product predominates.

4 0
3 years ago
A particular laser consumes 130.0 Watts of electrical power and produces a stream of 2.67×1019 1017 nm photons per second.
solniwko [45]

The missing question is:

<em>What is the percent efficiency of the laser in converting electrical power to light?</em>

The percent efficiency of the laser that consumes 130.0 Watt of electrical power and produces a stream of 2.67 × 10¹⁹ 1017 nm photons per second, is 1.34%.

A particular laser consumes 130.0 Watt (P) of electrical power. The energy input (Ei) in 1 second (t) is:

Ei = P \times t = 130.0 J/s \times 1 s = 130.0 J

The laser produced photons with a wavelength (λ) of 1017 nm. We can calculate the energy (E) of each photon using the Planck-Einstein's relation.

E = \frac{h \times c }{\lambda }

where,

  • h: Planck's constant
  • c: speed of light

E = \frac{h \times c }{\lambda } = \frac{6.63 \times 10^{-34}J.s  \times 3.00 \times 10^{8} m/s }{1017 \times 10^{-9} m }= 6.52 \times 10^{-20} J

The energy of 1 photon is 6.52 × 10⁻²⁰ J. The energy of 2.67 × 10¹⁹ photons (Energy output = Eo) is:

\frac{6.52 \times 10^{-20} J}{photon} \times 2.67 \times 10^{19} photon = 1.74 J

The percent efficiency of the laser is the ratio of the energy output to the energy input, times 100.

Ef = \frac{Eo}{Ei} \times 100\% = \frac{1.74J}{130.0J} \times 100\% = 1.34\%

The percent efficiency of the laser that consumes 130.0 Watt of electrical power and produces a stream of 2.67 × 10¹⁹ 1017 nm photons per second, is 1.34%.

You can learn more about lasers here: brainly.com/question/4869798

8 0
3 years ago
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