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Softa [21]
4 years ago
15

In a lead-acid battery, the electrodes are consumed. In this battery, Select one: a. the anode is PbO2. b. the cathode is Pb. c.

the cathode is PbSO4. d. the anode is PbSO4. e. the anode is Pb.
Chemistry
1 answer:
Gnoma [55]4 years ago
6 0

Answer:

The correct answer is option e.

Explanation:

The lead acid battery consists lead as an anode and lead oxide as a cathode. Both the electrodes are suspended in dilute sulfuric acid which act as an electrolyte.

At anode: Oxidation

Pb(s)+SO_4^{2-}(aq)\rightarrow PbSO_4(s)+2e^-

At cathode: Reduction

PbO_2+SO_4^{2-}(aq)+4H^+(aq)+2e^-\rightarrow PbSO_4(s)+2H_2O

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What type of reaction is  Zn + 2HCl > ZnCl2 + H2
Dmitry [639]
 this is the answer is 


Zn<span> + </span>HCl<span> = </span>ZnCl2<span> + </span>H2 <span> </span>
3 0
4 years ago
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Rachel has a sample containing 2 moles of carbon. How many atoms of carbon are in this sample?
Bumek [7]

Answer is: c. 1.204 × 10²⁴ atoms of carbon.

n(C) = 2 mol; amount of substance of carbon.

Na = 6.02·10²³ 1/mol; Avogadro constant (the number of constituent particles, in this example atoms, that are contained in the amount of substance given by one mole).

N(C) = n(C) · Na.

N(C) = 2 mol · 6.02·10²³ 1/mol.

N(C) = 12.04·10²³ = 1.204·10²⁴; number of carbon atoms in a sample.


5 0
3 years ago
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What is the percent yield of NH3 if the reaction of 26.3 g of H2 produces 79.0 g of NH3?
Anvisha [2.4K]

Answer:

\boxed{\text{53.3 \%}}

Explanation:

MM:           2.016      17.03

           N₂ + 3H₂ ⟶ 2NH3

m/g:            26.3  

1. Theoretical yield

(a) Moles of H₂

\text{Moles of H${_2}$} = \text{26.3 g H${_2}$} \times \dfrac{\text{1 mol H${_2}$}}{\text{2.016 g H${_2}$}} = \text{13.05 mol H${_2}$}

(b) Moles of NH₃

\text{Moles of NH${_3}$} = \text{13.05 mol H${_2}$} \times \dfrac{\text{2 mol NH${_3}$}}{\text{3 mol H${_2}$}} = \text{8.697 mol NH${_3}$}

(c) Theoretical yield of NH₃

\text{Mass of NH${_3}$} = \text{8.967 mol NH${_3}$} \times \dfrac{\text{17.03 g NH${_3}$}}{\text{1 mol NH${_3}$}} = \text{148.1 g NH${_3}$}

(d) Percent yield

\text{Percent yield} = \dfrac{\text{ actual yield}}{\text{ theoretical yield}} \times 100 \% = \dfrac{\text{79.0 g}}{\text{148.1 g}} \times 100 \% = \textbf{53.3 \%}\\\\\text{The percent yield is }\boxed{\textbf{53.3 \%}}

7 0
3 years ago
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In an ionic compound, the size of the ions affects the internuclear distance (the distance between the centers of adjacent ions)
gregori [183]

Answer:

The correct answer will be " RbF > RbCl > RbBr > Rbl".

Explanation:

The size of the given ions will be:

<u>RbCl:</u>

⇒  689kJ/mol

<u>RbBr:</u>

⇒  660kJ/mol

<u>Rbl:</u>

⇒  630kJ/mol

<u>RbF:</u>

⇒  785kJ/mol

Now according to the size, the arrangement will be:

⇒  (785kJ/mol) > (689kJ/mol) > (660kJ/mol) >(630kJ/mol)

⇒  RbF > RbCl > RbBr > Rbl

The bond among all opposite charging ions seems to be strongest whenever the ions were indeed small.

6 0
3 years ago
Does temperature affect the solubility rate?
8_murik_8 [283]
I think it does......

6 0
3 years ago
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