Answer:
232.5 g C2H6O2
Explanation:
The equation you need to use here is ΔTf = i Kf m
Since pure water freezes at 0 C, your ΔTf is just 4.46 C
i = 1 (ethylene glycol is a weak electrolyte)
Kf = molal freezing constant, which for water is 1.86 C/m
m = molality = x mols C2H6O2 / 1.15 kg H2O (don't know the moles of ethylene glycol we're dissolving yet)
Than,
4.46 C = 1.86 C/m (x mol C2H6O2 / 1.15 kg H2O)
Solve for x, you should get x = 2.75 mol C2H6O2
3.75 mol C2H6O2 (62 g C2H6O2 / 1 mol C2H6O2) = 232.5 g C2H6O2
Answer:
D:2
Explanation:
H is hydrogen, and the subscript represents the amount of atoms it has so H2SO is two hydrogens
The internal energy of the ideal gas is zero
The change in internal energy for an isothermal process is zero.
An ideal gas has no interactions between particles, therefore no intermolecular forces.
pressure change at constant temperature does not change the internal energy.
Adiabatic throttling expansion has less work done and lower heat flow.
That lower the internal energy.
The temperature decreases during the adiabatic expansion
Hence the internal energy of the ideal gas is zero
Learn more about the ideal gas on
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Question 4 is C. 13 I believe