The maximum value of the objective function is 26 and the minimum is -10
<h3>How to determine the maximum and the minimum values?</h3>
The objective function is given as:
z=−3x+5y
The constraints are
x+y≥−2
3x−y≤2
x−y≥−4
Start by plotting the constraints on a graph (see attachment)
From the attached graph, the vertices of the feasible region are
(3, 7), (0, -2), (-3, 1)
Substitute these values in the objective function
So, we have
z= −3 * 3 + 5 * 7 = 26
z= −3 * 0 + 5 * -2 = -10
z= −3 * -3 + 5 * 1 =14
Using the above values, we have:
The maximum value of the objective function is 26 and the minimum is -10
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Answer:
1 is to 2
Ie
1/2
Step-by-step explanation:
hope it helps
A little more info please?
Answer:
Step-by-step explanation:
Let's find our C value for the quadratic equation.
That is our C. Since we added 9 to one side, we have to do the same to the other. We get:
Now, lets form the left side as a binomial squared.
Let's square both sides now:
Now, we subtract 3 from both sides to isolate the variable, X:
This means that the answers are:
I do not understand your answers though. Answer A makes no sense, answer B is 221, answer C is 115, and answer D also does not make sense. If you could clarify this portion, maybe I can help you find your alphabetic answer
Answer:
Step-by-step explanation:
1 solution: x=13/3
