Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.
1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.
According to this theorem,
Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then
Take positive value x. You get
2. According to the previous theorem,
Then
Answer: 
This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then
This means that you cannot find solutions of this equation. Then CD≠2 cm.
Answer: No
Step-by-step explanation: The table does not have a function rule that is linear, quadratic, or cubic.
Because vol= length x width x height , and assuming that the height is 11.5 because breadth means width but you already have a width then, vol= 11.5 x 7.4 x 11.5, vol = 978.65
Answer:
a=10, b=5, c=2, d=12
Step-by-step explanation:
Multiply each variable together
5*2=10
8*3=24
10
/24x
the coefficients (numbers) can each be divided by 2
5
/12x
subtract the "x" exponents together
5
/12
The quadratic equation is given by:
y = 3x² + 10x - 8
The standard equation of a parabola is given by:
y = ax² + bx + c
Where a, b, c are constants
At point (4, 80):
80 = a(4)² + b(4) + c
16a + 4b + c = 80 (1)
At point (-3, -11):
-11 = a(-3)² + b(-3) + c
9a - 3b + c = -11 (2)
At point (-1, -15):
-15 = a(-1)² + b(-1) + c
a - b + c = -15 (3)
Solving equations 1, 2 and 3 simultaneously gives:
a = 3, b = 10, c = -8
Therefore the quadratic equation becomes:
y = 3x² + 10x - 8
Find out more on quadratic equation at: brainly.com/question/1214333
