Answer: center is (-4,2) radius is 4
Step-by-step explanation:
Equation of circle
is (X-A)^2+(X-B)^2=r^2
The center Of The circle is (A, B)
The radius Of The circle is r
Comparing the given equation and the equation of a circle we get the center Of The circle as (-4,2) and then radius as 4
What is the slope? We need the slope to find y
Answer:
Well from where the equation is now, I don't see any further things I can do. What is the context of the problem?
Step-by-step explanation:
PART A:
The given quadratic equation is 2x²-10x-8=0
The radicand is given by b²-4ac where a, b, and c are the constants in a quadratic form ax²+bx+c
From the given equation, we have
a = 2
b = -10
c = -8
Radicand b²-4ac = (-10)² - 4(2)(-8) = 100 + 64 = 164
The radicand is >0 hence the quadratic equation has two distinct roots
PART B:
4x²-12x+5 = 0
We can use the factorization method to solve the equation
Firstly, we multiply 4 by 5 to get 20
Then we find the pair of numbers that multiply gives 20 and sum gives -12
The pair of number is -2 and -10
Rewriting the equation
4x²-2x-10x+5 = 0
2x(2x-1)-5(2x-1) = 0
(2x-1)(2x-5) = 0
2x-1 = 0 and 2x-5 = 0
x = 1/2 and x = 5/2
Answer:
∠ YVZ = 56°
Step-by-step explanation:
∠ WVZ = 90° ( given ), thus
∠ WVY + ∠ YVZ = 90, substitute values
2x + 3x + 5 = 90
5x + 5 = 90 ( subtract 5 from both sides )
5x = 85 ( divide both sides by 5 )
x = 17
Thus
∠ YVZ = 3x + 5 = 3(17) + 5 = 51 + 5 = 56°