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julia-pushkina [17]
3 years ago
6

I need help asp !! Who ever answer is correct I will give them Brainiest

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
4 0

Answer:

5 faster than car 2

Step-by-step explanation:

find the slope abd divide

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What is the area of the figure:
Luba_88 [7]

For this case we have that the area of the triangle is given by:

A = \frac {b * h} {2}

Where:

b: It's the base

h: It's the height

We have to:

cos (45) = \frac {b} {24}\\b = 24 * cos (45)\\b = \frac {\sqrt {2}} {2} * 24\\b = 12 \sqrt {2}

The atura will be given by:

sin (45) = \frac {h} {24}\\h = 24 * sin (45)\\h = \frac {\sqrt {2}} {2} * 24\\h = 12 \sqrt {2}

So, the area is:

A = \frac {12 \sqrt {2} * 12 \sqrt {2}} {2}\\A=\frac{(12\sqrt{2})^2}{2}\\A = 144

Answer:

144

6 0
3 years ago
Read 2 more answers
Choose the correct vertex of the function f(x) = x2 - X + 2.
8_murik_8 [283]

Answer:

The vertex of the function is (\frac{1}{2}, \frac{7}{4})

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

f(x) = ax^{2} + bx + c

It's vertex is the point (x_{v}, y_{v})

In which

x_{v} = -\frac{b}{2a}

y_{v} = -\frac{\Delta}{4a}

Where

\Delta = b^2-4ac

If a<0, the vertex is a maximum point, that is, the maximum value happens at x_{v}, and it's value is y_{v}.

f(x) = x² - X + 2.

Quadratic equation with a = 1, b = -1, c = 2

So

\Delta = b^2-4ac = (-1)^2 - 4(1)(2) = 1 - 8 = -7

x_{v} = -\frac{(-1)}{2} = \frac{1}{2}

y_{v} = -\frac{-7}{4} = \frac{7}{4}

The vertex of the function is (\frac{1}{2}, \frac{7}{4})

4 0
3 years ago
Make a ten to find 8+4
Gnom [1K]
The answer is 12 because you got to add
3 0
3 years ago
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Ely walks 7/8 mile in 1/3 hour. what is his speed miles per hour?
alexdok [17]
21/8 miles per hour. Or 2 and 5/8 miles per hour
7 0
3 years ago
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A remainder of zero in the process of doing synthetic division tells you that you have found a root of the polynomial function a
Illusion [34]
From the Quotient-Remainder Theorem follows that for every f(x)  there exist unique polynomials q(x) and r(x) such that:
f(x)=h(x)q(x)+r(x),
where r(x) is called remainder.
If r(x)=0, then f(x)=h(x)q(x) and q(x) is adivisor. If q(x) is of form q(x)=x-a, then a is a root of f(x).


7 0
4 years ago
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