Two planes are the same altitude. From the airport , one plane is 50 km away in the direction of N°60 E and another is 80 km awa
1 answer:
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Answer:
78.5 km
Step-by-step explanation:
Measured at the airport, the angle between the two planes is ...
180° -60° -50° = 70°
The law of cosines tells us the distance between the planes is ...
d = √(50² +80² -2·50·80·cos(70°)) ≈ √6163.84 ≈ 78.5 . . . km
The planes are about 78.5 km apart.
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Answer:
∠NQP = 74°
Step-by-step explanation:
NPQ is a triangle.
We know the sum of 3 angles of a triangle is 180 degrees. So we can write:
N + P + Q = 180
2x + 34 + 2x + 2 = 180
Now, we can solve for x:
The measure of NQP is "2x+2", we plug in x = 36, and find the measure of NQP:
∠NQP = 2(36) + 2 = 74°