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Papessa [141]
2 years ago
9

Two planes are the same altitude. From the airport , one plane is 50 km away in the direction of N°60 E and another is 80 km awa

y in the direction of S50° E .How far apart are the two planes
Mathematics
1 answer:
djverab [1.8K]2 years ago
6 0

9514 1404 393

Answer:

  78.5 km

Step-by-step explanation:

Measured at the airport, the angle between the two planes is ...

  180° -60° -50° = 70°

The law of cosines tells us the distance between the planes is ...

  d = √(50² +80² -2·50·80·cos(70°)) ≈ √6163.84 ≈ 78.5 . . . km

The planes are about 78.5 km apart.

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Answer:

2x^2+8x-30 represents the total perimeter of the table, and if x = 3 the lentgh of entire rubber bumper is 12 feet.

Step-by-step explanation:

Perimeter is defined as the sum of sides.

For a rectangle having dimension length 'L' and breadth 'B' Since, rectangle has two sides equal.

Perimeter of rectangle = 2 ( length + breadth )

Here, given rectangle has dimension

Length = 2x^2-16 and breadth = -x^2+4x+1

Thus, perimeter of rectangle = 2(2x^2-16+(-x^2+4x+1))

                                              =2(2x^2-16-x^2+4x+1)

                                               =2(x^2+4x-15)

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Thus, perimeter of rectangle is 2x^2+8x-30   ........(1)

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Put x= 3 in (1) ,

2x^2+8x-30\Rightarrow 2(3)^2+8(3)-30 \Rightarrow 18+24-30=12

Thus, 2x^2+8x-30 represents the total perimeter of the table, and if x = 3 the lentgh of entire rubber bumper is 12 feet.




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