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Ghella [55]
3 years ago
14

Find the area of the triangle. 10 ft 14 ft The area of the triangle is square feet.

Mathematics
1 answer:
ivolga24 [154]3 years ago
8 0

Answer:

140

Step-by-step explanation:

times 10 and 14 together

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What is (0,6] n (6,8]?
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Suzanne made 2 gallons of punch to be divided equally among 10 people. How much punch did each person get
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Daniel is paid $10 per week for selling newspaper subscriptions. He is also paid $3.50 for each new customer (x) that signs up f
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Alright so, since it says that he eats at least $10 dollars no matter what we can basically leave that alone. next week have $3.50 for every new customer (x) so we could write this as $3.50x. and lastly we have Y the amount he will earn every week.

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5 0
3 years ago
F(x) = x + 4 and g(x) = 2x + 3, evaluate each expression.
Rom4ik [11]

Answer:

15.~f(g(2))=\Large\boxed{11}\\

16.~g(f(2.5))=\Large\boxed{16}

17.~g(f(-5))=\Large\boxed{1}

18.~f(g(-5))=\Large\boxed{-3}

Step-by-step explanation:

<h3>Given information</h3>

f(x)=x+4

g(x)=2x+3

<h3>Question 15. f(g(2))</h3>

<u>Substitute values into the first function</u>

g(2)=2(2)+3

g(2)=4+3

g(2)=7

<u>Substitute the values of the first function into the second</u>

f(g(2))=f(7)

f(7)=(7)+4

f(7)=\Large\boxed{11}

<h3>Question 16. g(f(2.5))</h3>

<u>Substitute values into the first function</u>

f(2.5)=(2.5)+4

f(2.5)=6.5

<u />

<u>Substitute the values of the first function into the second</u>

g(f(2.5))=g(6.5)

g(6.5)=2(6.5)+3

g(6.5)=13+3

g(6.5)=\Large\boxed{16}

<h3>Question 17. g(f(-5))</h3>

<u>Substitute values into the first function</u>

f(-5)=(-5)+4

f(-5)=-1

<u>Substitute the values of the first function into the second</u>

g(f(-5))=g(-1)

g(-1)=2(-1)+3

g(-1)=-2+3

g(-1)=\Large\boxed{1}

<h3>Question 18. f(g(-5))</h3>

<u>Substitute values into the first function</u>

g(-5)=2(-5)+3

g(-5)=-10+3

g(-5)=-7

<u>Substitute the values of the first function into the second</u>

f(g(-5))=f(-7)

f(-7)=(-7)+4

f(-7)=\Large\boxed{-3}

Hope this helps!! :)

Please let me know if you have any questions

7 0
1 year ago
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