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Umnica [9.8K]
3 years ago
13

(a^4(3a^2b)^3)/((3ab^2)^-1) exponent has to be postive and has to be simplified

Mathematics
1 answer:
Levart [38]3 years ago
5 0

Answer: 81a^8b^12

Step-by-step explanation:

When you have an exponent to an exponent multiply the exponents.

 

(3a^2b^3)^4

=81a^8b^12

Ed

To do this problem, you need to raise each of the individual terms inside the parentheses

to the 4th power.

In other words:

Now you can recognize that 3%5E4 is 3*3*3*3 and this product is 81. So you can substitute

81 in place of 3%5E4 and the problem is reduced to:

.

81%2A%28a%5E2%29%5E4%2A+%28b%5E3%29%5E4

.

Next look at %28a%5E2%29%5E4. You can get an equivalent form of this by multiplying the exponent

4 by the exponent 2 to get a%5E8. You can also think of %28a%5E2%29%5E4 as being a%5E2

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artcher [175]

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4(0.5f - 0.25) = 6 + f       Distribute 4 into (0.5f - 0.25)

(4)0.5f + (4)(-0.25) = 6 + f

2f - 1 = 6 + f        Subtract f on both sides to get "f" on one side of the equation

2f - f - 1 = 6 + f - f

f - 1 = 6       Add 1 on both sides to get "f" by itself

f - 1 + 1 = 6 + 1

f = 7

PROOF

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4(0.5(7) - 0.25) = 6 + 7

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